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ASHA 777 [7]
2 years ago
14

Explain any differences in the pulse rate at rest and after exercise ( in own words btw^^

Chemistry
1 answer:
timurjin [86]2 years ago
5 0

Answer:

Pulse rate depends on the activity we do, while exercising theres need of more oxygen so it increases but while at rest body requires less oxygen so low pulse rate.

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Which term is dependent on temperature?
Romashka-Z-Leto [24]
1. E. None of the Above
2. D. x + y
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3 years ago
How is helium which is produced by the conversion of hydrogen into energy related to the solar core
qaws [65]
The sun's core is where Hydrogen atoms produce energy as they convert to molecules of Helium. Helium that is produced by the conversion of hydrogen into energy is related to the solar core in the sense that the conversion process produces energy captured in the core. I hope this helps you. 
3 0
3 years ago
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A sample of gas originally at 25 C and 1.00 atm pressure in a 2.5 L container is allowed to expand until the pressure is 0.85 at
aivan3 [116]

Answer:

Final volumeof the gas = 2.84 L

Explanation:

The formular to be used here is the general gas equation. the formular is being used because it gives the relationship between the three gas parameters (volume, temperature and pressure) mentioned.

The general gas equation is given as;

\frac{P1V1}{T1} = \frac{P2V2}{T2}

where;

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = Final pressure

V2 = Final volume

T2 = Final temperature

From the question,

P1 = 1.00 atm

P2 = 0.85atm

T1 = 25C + 273 = 298K (Converting to kelvin)

T2 = 15C + 273 = 288K (Converting to kelvin)

V1 = 2.5L

V2 = ?

from the equation, making V2 subject of formula we have;

V2 = \frac{T2P1V1}{T1P2}

V2 = (1*2.5*288)/(298*0.85) = 2.84 L.

5 0
4 years ago
A bracelet containing 0.364 mol of metal atoms is 66% gold. How many particles of gold atoms are in the bracelet?
Katyanochek1 [597]

Answer:

129.9g

Explanation:

196.966569 * 0.66 = 129.9g

7 0
3 years ago
Dry air (0% humidity) is approximately 78% N2, 21% O2, and 1% Ar by moles. Calculate the molar mass and density of dry air at 0
gtnhenbr [62]

Answer:

The molar mass of dry air = 28.94

Density = 1.29

Explanation:

Mm of N2= 28, Mm of O2= 32, Mm Ar= 39.9

78% of N2 by mole give = 0.78×28= 21.84

21% of O2 by mole give = 0.21× 32= 6.72

1% of At by mole give = 0.01× 39= 0.39

Hence overall molecular weight of air = 21.84+6.72+0.39= 28.94

Density = m/ v,

1- mole of air occupy 22.4dm^3 volume

Density= 28.94/22.4= 1.29

6 0
3 years ago
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