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BARSIC [14]
3 years ago
14

As the temperature of a reaction is increased, the rate of the reaction increases because the . (A) reactant molecules collide m

ore frequently with less energy per collision. (B) reactant molecules collide less frequently. (C) reactant molecules collide with greater energy per collision. (D) reactant molecules collide less frequently and with greater energy per collision. (E) activation energy is lowered.
Chemistry
1 answer:
vredina [299]3 years ago
5 0

Answer:

C

Explanation:

Temperature is the measure of "hotness" of a system. When temperature increases, the kinetic energy of the particles increase. So they will collide with greater energy per collision.

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PLEASE HELP ASAP. I WILL MARK BRAINLIEST!!!
iris [78.8K]

I Cant Answer your question but maybe this will help

Volume Changes for Gases

Particles in a gas have more freedom of movement than they do in a liquid. According to the ideal gas law, the pressure (P) and volume (V) of a gas are mutually dependent on temperature (T) and the number of moles of gas present (n). The ideal gas equation is PV = nRT, where R is a constant known as the ideal gas constant. In SI (metric) units, the value of this constant is 8.314 joules ÷ mole - degree K.

Pressure is constant: Rearranging this equation to isolate volume, you get: V = nRT ÷ P, and if you keep the pressure and number of moles constant, you have a direct relationship between volume and temperature: ∆V = nR∆T ÷ P, where ∆V is change in volume and ∆T is change in temperature. If you start from an initial temperature T0 and pressure V0 and want to know the volume at a new temperature T1 the equation becomes:

V1 = [n • R • (T1 - T0) ÷ P] +V0

Temperature is constant: If you keep the temperature constant and allow pressure to change, this equation gives you a direct relationship between volume and pressure:

V1 = [n • R • T ÷ (P1 - P0)] + V0

Notice that the volume is larger if T1 is larger than T0 but smaller if P1 is larger than P0.

Pressure and temperature both vary: When both temperature and pressure vary, the the equation becomes:

V1 = n • R • (T1 - T0) ÷ (P1 - P0) + V0

Plug in the values for initial and final temperature and pressure and the value for initial volume to find the new volume.

6 0
3 years ago
Read 2 more answers
Which is a balanced chemical equation? A. C7H16 + 5O2 6CO2 + 4H2O B. C7H16 + 11O2 7CO2 + 8H2O C. C7H16 + 14O2 7CO2 +5H2O D. C7H1
nadya68 [22]

Answer:

\boxed{\text{B.}}

Explanation:

B.

\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O

BALANCED. 7C, 16H, and 22O on each side of equation.

A.

\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O

NOT BALANCED. 7C on left and 6C on right.

C.

\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O

NOT BALANCED. 16H on left and 10H on right.

D.

\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O

NOT BALANCED. 7C on left and 14C on right.

3 0
3 years ago
2.0 moles of a monatomic ideal gas undergoes an isobaric process in which the temperature changes from 260 k to 320 k. what is t
Alik [6]

The change in the internal energy of the gas is 1.5×10∧3 J.

The internal energy of an ideal gas is directly proportional to the temperature of the gas:

ΔE = 3/2 × n × R × ΔT

ΔT = 320 K - 260 K

ΔT = 60 K; change of the temperature

n = 2.0 mol: amount of a monatomic ideal gas

R = 8.1 J/mol×K;the ideal gas constant

ΔE = 3/2 × 2 mol × 8.1 J/mol×K × 60 K

ΔE = 1500 J

ΔE = 1.5×10∧3 J;  the internal energy of the gas

Isobaric process is a type of process in which the pressure of the system stays constant.

More about an isobaric process: brainly.com/question/28106078

#SPJ4

4 0
1 year ago
Why is pressure on Jupiter enormous?
Evgen [1.6K]
Deep under Jupiter's<span> clouds is a </span>huge<span> ocean of liquid metallic hydrogen. On Earth, hydrogen is usually gas. But on </span>Jupiter<span>, the </span>pressure<span> is so great inside its atmosphere that the gas becomes liquid. As </span>Jupiter<span> spins, the swirling, liquid metal ocean creates the strongest magnetic field in the solar system.</span>
7 0
3 years ago
25 g of a compound is added to 500 mL of water if the freezing point of the resulting solution is
vlabodo [156]

Answer:

a)   119 g/mol

Explanation:

-We apply the formula for freezing point depression to obtain the molality of the solution:

\bigtriangleup T_f=K_fm, \  \ K_f=1.36\textdegree C/m\\\\\therefore m=\frac{\bigtriangleup T_f}{K_f}\\\\=\frac{0.57\textdegree C}{1.36\textdegree C}\\\\=0.4191\ mol/Kg\\\\

#We use the molality above to calculate the molar mass:

m=\frac{0.4191\ mol}{1\ Kg}=\frac{25\ g}{0.5\ Kg}\\\\\therefore 1 \ mol=\frac{25\ g}{0.5\ Kg}\times\frac{1\ Kg}{ 0.4191}\\\\=119.3033\approx 119\ g/mol

Hence, the molar mass of the compound is 119 g/mol

5 0
3 years ago
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