If a solution(s) exists y=y so we can say:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 factor
(x-2)(x+1)=0
So x=-1 and 2, using y=-2x+2 we find:
y(-1)=4 and y(2)=-2
So the two solutions occur at the points:
(-1,4) and (2,-2)
Correct the answer is -55
Answer:
1. (-7, 5 ) and (-1, 3)
(3-5)/(-1+7)= -2/6 = -1/3
y - 5 = (-1/3)(x + 7)
y - 5 = (-1/3)x - 7/3
y - 15/3= (-1/3)x - 7/3
y = (-1/3)x + 8/3
2. (-1-3)/(3-0)= -4/3
y + 3 = (-4/3)(x + 1)
y + 3 = (-4/3)x - 4/3
y + 9/3 = (-4/3)x - 4/3
y = (-4/3)x + 5/3
the answer is neither
