Factor the following:
12 x^4 - 42 x^3 - 90 x^2
Factor 6 x^2 out of 12 x^4 - 42 x^3 - 90 x^2:
6 x^2 (2 x^2 - 7 x - 15)
Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
6 x^2 x (2 x + 3) - 5 (2 x + 3)
Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
Answer: 6 x^2 (2 x + 3) (x - 5)
Answer:
A) x = 6
Step-by-step explanation:
4x - 2x + 6 = x + 12
Combine like terms
2x +6 = x+12
Subtract 6 from each side
2x+6-6 = x+12-6
2x = x+6
subtract x
2x-x = x+6-x
x = 6
Answer: 10
Step-by-step explanation:
add 2.75 to 0
Answer:
B= 90
C= 80
D= 100
Step-by-step explanation:
So let’s start with the bottom angles.
We know that the adjacent angles in a parallelogram add up to 180° so our equation would be
. So let’s simplify it b and b are both the same variables so we will get 2b and -10 + 10 is 0 so we get the following equation
.
So now we divide 180 and 2 and we get 90 as b.
So one side will be 100 because of the +10 and the other 90 because of the -10.
Now for the next side.

So we know that b+10 is adjacent to c so 180-100 is 80, so 80 is c.
Now for d.
b-10 is 80 so 180-80 is 100, so d is 100.
The equation 2v-41=0 can be used to find the number of visits that would make two memberships cost the same amount.
Step-by-step explanation:
Given,
Per month charges of type 1 = $86
Per visit charge = $3
Let,
v be the number of visits.
T(v) = 3v+86
Per month charges of type 2 = $45
Per visit charge = $5
P(v) = 5v+45
For same amount to be charged;
T(v) = P(v)

The equation 2v-41=0 can be used to find the number of visits that would make two memberships cost the same amount.