Answer:
324
Step-by-step explanation:
Given:
Find:
First, find f(x):
Now,
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
Answer:
128.605 m²
Step-by-step explanation:
Find the areas of the top triangle, and the bottom triangle and add them together.
The top triangle consists of 2 smaller triangles. Look at the larger one, the height is 4.93 and the base is 17. The area is...
A = (1/2)(17)(4.93)
A = 41.905 m²
The bottom triangle consists of 2 smaller triangles. Look at the larger one, the height is 10.2 and the base is 17. The area is...
A = (1/2)(17)(10.2)
A = 86.7 m²
The total area is 41.905 m² + 86.7 m² = 128.605 m²
Hello,
tan t /(sec t -cos t)= sin t/(cos t *(1/cos t -cos t))
=sin t/(cos t*(1-cos ²t)/cos t))
=sin t/sin² t=1/sin t [or=cosec t.]
is equal to 2x, since it is the derivative of
.
