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BabaBlast [244]
3 years ago
8

assume that random guesses are made for 9 multiple choice questions on an SAT test, so that there are n=9 trials, each with prob

ability of success (correct) given by p=0.6. find the indicated probability for the number of correct answers. find the probability that the number x of correct answers is fewer than 4.
Mathematics
1 answer:
Orlov [11]3 years ago
8 0

Answer:

though this looks difficult. It's easier than you think. Just not visible until its visible. If I knew the answer, i would have told you... sorry.

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Correct question:

A deck of cards contains RED cards numbered 1,2,3, BLUE cards numbered 1,2,3,4, and GREEN cards numbered 1,2. If a single card is picked at random, what is the probability that the card is BLUE OR has an ODD number?

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Step-by-step explanation:

Number of red cards = 3 (1,2,3)

Number of blue cards = 4 (1, 2, 3, 4)

Number of green cards = 2 (1,2)

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Probability of picking a blue card OR has an odd number

P(picking a blue card ) = required outcome / possible outcome

P( picking a blue card ) = 4/52 = 1/13

P( odd number card ) = 6/52 = 3/26

P(blue and odd) = 2/52 = 1/26

P(picking a blue card or an odd number )

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P(picking a blue) + (P(picking an odd) - P(picking a blue odd)

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