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harina [27]
3 years ago
14

A container is shaped like a rectangular solid with sides of 3 inches, 3 inches, and 11

Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0
It would be about 4/10 of a gallon
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Brett warmed up for his basketball game by running around the court 3 times . If the court is 84 feet by 50 feet, how many feet
lana [24]

Answer:

804 feet

Step-by-step explanation:

Given: Dimension of a basketball court is 84 feet by 50 feet.

Considering the shape of basketball court is in rectangle shape.

∴ Finding the perimeter of rectangle to know total number of feet in one round.

Perimeter of rectangle= 2(l+w)

where, l= length

           w= width

∴ Perimeter of rectangular court= 2(84\ feet + 50\ feet)

⇒ Perimeter of rectangular court= 2(134\ feet)

Opening parenthesis

⇒ Perimeter of rectangular court= 2\times 134\ feet= 268\ feet

Hence, Brett run 268 feet in one round of warm up.

As given, Brett ran around the court 3 times.

∴ Total number of feet= 268\ feet\times 3= 804\ feet

Hence, Brett jog for 804 feet.

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3 years ago
Find the quotient 54÷3=
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60/3=20 57/3=19 54/3=18
7 0
4 years ago
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Find the measure of angle b if angle a is 22 degrees and the whole angle is 300 degrees
Dima020 [189]

Answer:

a  = 278^{\circ}

Step-by-step explanation:

Given

b = 22^{\circ}

Whole\ Angle = 300^{\circ}

Required

Find the measure of a

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a + b = Whole\ Angle

This gives:

a + 22^{\circ} = 300^{\circ}

Subtract 22 from both sides

a + 22^{\circ}-22^{\circ} = 300^{\circ}-22^{\circ}

a  = 300^{\circ}-22^{\circ}

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6 0
3 years ago
Evaluate the expression when a= 1/4 and b = 6.<br> 16a2 – 4b=
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Step-by-step explanation:

HERE,

a=\bold{\dfrac{1}{4}   }

b=6

so,

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

\bold{16a^2-4b   }

\bold{16\times(\dfrac{1}{4})^2-4\times 6   }

\bold{ 16\times \dfrac{1}{16}-24 }

\bold{\cancel{16}\times \dfrac{1}{\cancel{16}}-24   }

\bold{1-24   }

\bold{ -23  }

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3 years ago
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!!
Andreas93 [3]

9514 1404 393

Answer:

  \text{for }f(x)=\log_b(x),\text{ the inverse is }f^{-1}(x)=b^x

Step-by-step explanation:

As with any function and its inverse, you can find the inverse of ...

  f(x)=\log_b(x)

by solving the equation x = f(y).

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