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2 years ago

Solve the inequality 5p -3 < 7 + 3p for p

Mathematics

1 answer:

KiRa [710]2 years ago

5 0

Step-by-step explanation:

p<5 that's the answer for the question

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A caterer charges a $30 fee plus an additional $6.50 per person. She determines the total cost, C, for x people by using the equ

emmainna [20.7K]

Answer:

$550

Step-by-step explanation:

In this question, we have to find how much a party would cost for 80 people.

We know that our equation is C = 6.50x + 30

"x" is the amount of people.

To found our answer, we would plug in 80 to "x" to find the total cost.

Solve:

C = 6.50(80) + 30

C = 520 + 30

C = 550

This means that the cost of the party for 80 people would be $550.

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2 years ago

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3 years ago

Read 2 more answers

Carmen has 4 baby bunnies. Each bunny weighs 1/5 of a pound. How much do the bunnies weigh all together?

Anestetic [448]

Step-by-step explanation:

The answer is 0.8 as a fraction is 4/5

4 0

2 years ago

It takes 12 hours for a single hose to fill a large vat. When a second hose is added, the vat can be filled in 4 hours. How many

aksik [14]

<h3>Answer:</h3>

6 hours

<h3>Step-by-step explanation:</h3>

The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.

That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.

The second hose alone can fill the vat in 6 hours.

_____

The first hose's rate of doing work is ...

... (1 vat)/(12 hours) = (1/12) vat/hour

If h is the second hose's rate of doing work, then working together their rate is ...

... (1/12 vat/hour) + h = (1/4 vat/hour)

... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour

... h = 1/6 vat/hour

so will take 6 hours to fill 1 vat.

8 0

3 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago