Question 3 has got me lost, need help much appreciated
1 answer:
Answer:
E. a = 2
Step-by-step explanation:
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The question is asking for what the value of a is for the given polynomial.
They gave you a factor to that polynomial, (x+a), and told you that a can be any real number beside 0.
You might remember that when you factor an equation, all you're doing is finding for what value of x will give you an answer of 0.
This is what you're doing now but in reverse. You're given x+a as a factor, so you know that x=-a will make the function equal 0.
So plug x=-a into the function and solve for a. You'd find that you get a=0 and a=2; however, the question stated that a≠0, so the only answer left is a=2.
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Answer:
B) x = e^x
Step-by-step explanation:
The graphs of y = e^x and y = x never intersect, so the solution set will be the empty (null) set for ...
x = e^x
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There is one intersection of y=x with cos(x) and with sin(x). There are an infinite number of solutions for x = tan(x).
