It's actually this question
1 answer:
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Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
_____
* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
If those two are your only choices then the answer is none of the above.
<em>Attached is a cumulative frequency table for your data.</em>
If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.
The answer is then none of the above or find one that matches the table attached.
<em>Attached is a cumulative frequency table for your data.</em>
If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.
The answer is then none of the above or find one that matches the table attached.