1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.
Step-by-step explanation:
To find a solution to this inequality, we need to get 
to one side of the equation by itself. Since we have 
on the left-hand side of the equation, we can get
Answer:
1/2
Step-by-step explanation:
2 red marbles, 3 blue marbles, and 1 green marble= 6 marbles
P( blue) = blue /total
= 3 /6
= 1/2
Answer:
3y + 5x = 0
Step-by-step explanation:
The slope of the line = (y2-y1) / (x2-x1) = (5-0)/(-6-(-3))
= 5 / -3 = -5/3
Using the point-slope form , the line that passes through the origin and parallel to this line is
y - 0 = -5/3(x - 0)
y = -5/3 x
Multiply through by 3:-
3y = -5x
5x + 3y = 0
