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3 years ago

What is the least common multiple of both 9 and 12

2 answers:

8 0

The least common multiple can be found by prime factorization or simpy listing the factors! You must know what the least common multiple that goes into 9 and 12.
Prime factorization of 9 and 12 is 3 so 3x2x2x3=36
Or you can list the factors
9: 9,18,24,36
12: 12,24,36
So the least common multiple is 36

Crank3 years ago

3 0

LCM is found by finding the factors of both and making sure that both are inthere
9=3 times 3
12=2 times 2 times 3
common one is 3
so we have to have at least 2 threes and 2 twos
2 times 2 times 3 tiimes 3=36
answer is 36

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Step-by-step explanation:

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3 years ago

Rectangle A measures 10 inches by 8 inches. Rectangle B is an enlarged copy of Rectangle A. Select all of the measurement pairs

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Answer:

See Explanation

Step-by-step explanation:

Given

Rectangle A:

$Length: 10\ in$

$Width: 8\ in$

Required

Determine the possible dimensions of Rectangle B

The question has missing options; however, the question can still be solved.

Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B

Take for instance, the measurements of Rectangle B are

$Length: 15 in$

$Width: 12 in$

Divide the corresponding lengths of B by A to get the enlargement ratio

$Ratio = \frac{B}{A}$

For length:

$Ratio = \frac{15}{10}$

$Ratio = 1.5$

For width

$Ratio = \frac{12}{8}$

$Ratio = 1.5$

Notice that both ratios are the same.

For this measurement of B, we can conclude that B is an enlargement of A

Assume another measurements for B

$Length: 20\ in$

$Width: 10\ in$

Calculate Ratios

$Ratio = \frac{B}{A}$

For length:

$Ratio = \frac{20}{10}$

$Ratio = 2$

For width

$Ratio = \frac{10}{8}$

$Ratio = 1.25$

Notice that, both ratios are not equal.

For this measurement of B, we can conclude that B is not an enlargement of A

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igor_vitrenko [27]

Answer:

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Step-by-step explanation:

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