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Harrizon [31]
3 years ago
5

What is the least common multiple of both 9 and 12

Mathematics
2 answers:
AnnZ [28]3 years ago
8 0
The least common multiple can be found by prime factorization or simpy listing the factors! You must know what the least common multiple that goes into 9 and 12.
Prime factorization of 9 and 12 is 3 so 3x2x2x3=36
Or you can list the factors
9:   9,18,24,36
12: 12,24,36
So the least common multiple is 36
Crank3 years ago
3 0
LCM is found by finding the factors of both and making sure that both are inthere
9=3 times 3
12=2 times 2 times 3
common one is 3
so we have to have at least 2 threes and 2 twos
2 times 2 times 3 tiimes 3=36
answer is 36
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Bad White [126]
Answer is B, the graph increases by about 0.28 per year
8 0
3 years ago
Hope u can do it HELP MATH
Nostrana [21]

Answer:

the right answer would be 13

5 0
3 years ago
Read 2 more answers
Which of the following is not a rational number?<br><br><br> Help please
Pavlova-9 [17]
A, because negative is not rational
3 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
A number cube with faces labeled from 1 to 6 will be rolled once.
kramer

Answer:

\Omega=\{1,2,3,4,5,6\}

A=\{1,2,3,4\}

Step-by-step explanation:

<u>Sample Space</u>

The sample space of a random experience is a set of all the possible outcomes of that experience. It's usually denoted by the letter \Omega.

We have a number cube with all faces labeled from 1 to 6. That cube is to be rolled once. The visible number shown in the cube is recorded as the outcome. The possible outcomes are listed as the sample space below:

\Omega=\{1,2,3,4,5,6\}

Now we are required to give the outcomes for the event of rolling a number less than 5. Let's call A to such event. The set of possible outcomes for A has all the numbers from 1 to 4 as follows

A=\{1,2,3,4\}

3 0
3 years ago
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