Answer:
p = - 5, p = - 1
Step-by-step explanation:
Given
- 
= 
Multiply through by the LCM of (p - 5)(p + 3)
3p(p + 3) - 2(p - 5) = p(p - 5) ← distribute parenthesis
3p² + 9p - 2p + 10 = p² - 5p
3p² + 7p + 10 = p² - 5p ( subtract p² - 5p from both sides )
2p² + 12p + 10 = 0 ← divide through by 2
p² + 6p + 5 = 0 ← in standard form
(p + 1)(p + 5) = 0 ← in factored form
Equate each factor to zero and solve for p
p + 1 = 0 ⇒ p = - 1
p + 5 = 0 ⇒ p = - 5
Answer:
Step-by-step explanation:
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?
Two consecutive year positive integers are represented by
x and x + 1
First integer = x
Second integer = y
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.
This is represented mathematically as:
x² = 364 + 5(x + 1)
x² = 364 + 5x + 5
x² -5x -5 - 364
x² - 5x - 369
Hi!
When following the order of operations, A. Parantheses (or brackets) come first. =)
2 3/4 divided by 7=0.39285714285
Answer:
a and b
Step-by-step explanation:
