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2 years ago

If the side links 27 and 27 are halved, then which of the following statements about its area will be true.

Mathematics

1 answer:

Alenkinab [10]2 years ago

4 0

Answer: 1:4

It doesn't matter what the original side lengths were. If both dimensions are divided by 2, (halved) the Area of the new square will be 1/4 the Area of the original square.

Step-by-step explanation:

But to prove it: 27×27 = 729 .

27/2 = 13.5 . 13.5 × 13.5 = 182.25

729/182.25 = 4 .or 182.25/729 = 0.25

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maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

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