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kogti [31]
3 years ago
6

The __________ assumption necessary for a linear programming model to be appropriate means that the contribution to the objectiv

e function and the amount of resources used in each constraint are in accordance to the value of each decision variable.
Computers and Technology
1 answer:
o-na [289]3 years ago
6 0

Answer:

The correct answer to the following question will be Additivity.

Explanation:

In linear programming, there are four mathematical assumptions such as :

  • Proportionality
  • Additivity
  • Divisibility
  • Certainty

The fact that the algebraic sum of the individual weighted effect is equal to the combined effect of the variables in an equation. Thus, the amount that ensures the total records used can be found by totaling the number of resources and the objective function used for all variables of decision is known as Additivity.

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You have deployed several 802.11b wireless networks at your company's location. Recently, users complained that they were having
SOVA2 [1]

Answer:

The correct answer to the following question is Microwave ovens.

Explanation:

Because microwave ovens and the WIFI(Wireless Fidelity) both are operated at the same frequency that is 2.4 GHz.

It is not a magic, of course, logically explainable effects the radio waves. When the devices use WiFi signals to connect to the Internet then these signals are sent with the radio waves and despite all the advanced features of wireless interference can happen.

7 0
3 years ago
5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0
3 years ago
Your mother wants to purchase a larger hard drive for her computer and asks you to see what type of drive interface she has. her
Darya [45]
Your mom has what is called a Parallel ATA interface. Her computer is very old and I suggest more than just a hard drive :)
5 0
3 years ago
Read 2 more answers
Assume that name is a variable of type String that has been assigned a value.Write an expression whose value is a String contain
zhuklara [117]

Answer:

#read value of name

name=input("Enter name:")

#find and ptint the last character of the string

print("last character of string is:",name[-1])

Explanation:

Read a string from user and assign it to variable "name".Find its last character as "name[-1]". Since name is character array,so name[-1] will give the last character of the array.

Output:

Enter name:Smith                                                                                                          

last character of string is: h

6 0
3 years ago
JAVA PROGRAMMING
VashaNatasha [74]

Answer:

See explaination

Explanation:

import java.util.Scanner;

public class GtldValidation {

public static void main (String [ ] args) {

Scanner scnr = new Scanner(System.in);

// Define the list of valid core gTLDs

String [ ] validCoreGtld = { ".com", ".net", ".org", ".info" };

// FIXME: Define an array named validRestrictedGtld that has the names

// of the restricted domains, .biz, .name, and .pro

String [] validRestrictedGtld={".biz",".name",".pro"};

String inputName = "";

String searchName = "";

String theGtld = "";

boolean isValidDomainName = false;

boolean isCoreGtld = false;

boolean isRestrictedGtld = false;

int periodCounter = 0;

int periodPosition = 0;

int i = 0;

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

while (inputName.length() > 0) {

searchName = inputName.toLowerCase();

isValidDomainName = false;

isCoreGtld = false;

isRestrictedGtld = false;

// Count the number of periods in the domain name

periodCounter = 0;

for (i = 0; i < searchName.length(); ++i) {

if (searchName.charAt(i) == '.') {

++periodCounter;

periodPosition = i;

}

}

// If there is exactly one period that is not at the start

// or end of searchName, check if the TLD is a core gTLD or a restricted gTLD

if ((periodCounter == 1) &&

(searchName.charAt(0) != '.') &&

(searchName.charAt(searchName.length() - 1) != '.')) {

isValidDomainName = true;

}

if (isValidDomainName) {

// Extract the Top-level Domain name starting at the period's position. Ex:

// If searchName = "example.com", the next statement extracts ".com"

theGtld = searchName.substring(periodPosition);

i = 0;

while ((i < validCoreGtld.length) && (!isCoreGtld)) {

if(theGtld.equals(validCoreGtld[i])) {

isCoreGtld = true;

}

else {

++i;

}

}

// FIXME: Check to see if the gTLD is not a core gTLD. If it is not,

// check to see whether the gTLD is a valid restricted gTLD.

// If it is, set isRestrictedGtld to true

}

System.out.print("\"" + inputName + "\" ");

if (isValidDomainName) {

System.out.print("is a valid domain name and ");

if (isCoreGtld) {

System.out.println("has a core gTLD of \"" + theGtld + "\".");

}

else if (isRestrictedGtld) {

System.out.println("has a restricted gTLD of \"" + theGtld + "\".");

}

else {

System.out.println("does not have a core gTLD."); // FIXME update message

}

}

else {

System.out.println("is not a valid domain name.");

}

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

}

return;

}

}

8 0
3 years ago
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