I believe its true because you can expand or collapse sections of it
<u><em>Answer:</em></u>
<u><em>The speed is </em></u>
<u><em>=
</em></u>
<u><em>30
</em></u>
<u><em>m
</em></u>
<u><em>s
</em></u>
<u><em>−
</em></u>
<u><em>1
</em></u>
<u><em>
</em></u>
<u><em>Explanation:
</em></u>
<u><em>The speed of a wave is given by
</em></u>
<u><em>
</em></u>
<u><em>speed
</em></u>
<u><em>(
</em></u>
<u><em>m
</em></u>
<u><em>s
</em></u>
<u><em>−
</em></u>
<u><em>1
</em></u>
<u><em>)
</em></u>
<u><em>=
</em></u>
<u><em>frequency(Hz)
</em></u>
<u><em>×
</em></u>
<u><em>wavelength (m)
</em></u>
<u><em>
</em></u>
<u><em>The frequency is </em></u>
<u><em>f
</em></u>
<u><em>=
</em></u>
<u><em>100
</em></u>
<u><em>H
</em></u>
<u><em>z
</em></u>
<u><em>
</em></u>
<u><em>The wavelength is </em></u>
<u><em>λ
</em></u>
<u><em>=
</em></u>
<u><em>0.3
</em></u>
<u><em>m
</em></u>
<u><em>
</em></u>
<u><em>The speed is
</em></u>
<u><em>
</em></u>
<u><em>v
</em></u>
<u><em>=
</em></u>
<u><em>λ
</em></u>
<u><em>f
</em></u>
<u><em>=
</em></u>
<u><em>0.3
</em></u>
<u><em>⋅
</em></u>
<u><em>100
</em></u>
<u><em>=
</em></u>
<u><em>30
</em></u>
<u><em>m
</em></u>
<u><em>s
</em></u>
<u><em>−
</em></u>
<u><em>1
</em></u>
<u><em>
</em></u>
<u><em></em></u>
<u><em></em></u>
<u><em></em></u>
Answer:
Theoretically one could design an architecture that would address 16 GB of memory with 32-bits of unique addresses.
Explanation:
Answer:
Secure Authentication involves a combination of the following three information
Explanation:
Generally, it is important that users have access to secure sources of information or data. These data will be used by the users to get access to their platform such as account details. The user should also be the only person that has access to his or her vital information. This should not be disclosed to any other person.
For the view of Exercise 4.18, explain why the database system would not allow a tuple to be inserted into the database through this view.
For reference
For the database of Figure 4.12, write a query to find the ID of each employee with no manager. Note that an employee may simply have no manager listed or may have a null manager. Write your query using an outer join and then write it again using no outer join at all.
OUTER JOIN
select e.ID from employee e left outer join manages m on e.ID = m.ID
where m.manager_id is null;
NO OUTER
select e.ID from employee e where e.ID not in (select m.ID from manages m) or e.ID in (select m.ID from manages m where m.manager_id is null);