Answer:
The drawing of the free body diagram is in the attachment.
Explanation:
In order to draw a<em> free body diagram</em>, you have to include in the drawing all the acting forces in the box for the given situation.
The acting forces are:
-The normal force (N), which is the contact force that the inclined plane applies to the box. This force is perpendicular to the contact surface.
-The weight force (W), which is due to the force of gravity on the box. The direction of the weight force is vertical (perpendicular to the ground)
-The friction force (Fs), which in this case is the static friction force because the box is in rest. The direction of this force is opposite to the direction of the movement.
Therefore, you have to draw the inclined plane, the box and the acting forces (See the attachment)
Answer
given,
x = (3.9 cm)sin[(9.3 rad/s)πt]
general equation of displacement
x = A sin ω t
A is amplitude
now on comparing
c) Amplitude =3.9 cm
a) frequency =
f = 4.65 Hz
b) period of motion
T = 0.215 s
d) time when displacement is equal to x= 2.6 cm
x = (3.9 cm)sin[(9.3 rad/s)πt]
2.6 = (3.9 cm)sin[(9.3 rad/s)πt]
sin[(9.3 rad/s)πt] = 0.667
9.3 π t = 0.73
t = 0.025 s