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matrenka [14]
3 years ago
5

How much force do you push down on the Earth with? (Hint: 1kg is about 2 pounds).​

Physics
2 answers:
e-lub [12.9K]3 years ago
6 0

The force with which I push down on the Earth is PRECISELY equal to the force with which the Earth pushes UP on me.  

I weigh EXACTLY the same amount on the Earth as the Earth weighs on me.  Find THAT amount, and you'll have the answer to the question.

(Hint:  1 kg is a mass, and 2 pounds is a force, so they can never be equal.  1kg weighs about 2.2 pounds IF it happens to be on Earth.  But if the same 1kg is on the Moon, then it weighs about 5.8 ounces.  And if it happens to be on Mars, then it weighs about 13.3 ounces.  The same kilogram weighs different weights in different places.)

On a good day, I push down on the Earth with about 890 Newtons of force.  No matter how hard I try, I can never push more or less than that.

Gennadij [26K]3 years ago
3 0

Answer: 100lbs

Explanation: The Earth pushes you down at 100lbs, so you push down the earth by 100lbs which is enough to keep you firmly attached to the ground and not allow you to jump more than a couple of feet.

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Jin knows that the initial internal energy of a closed system is 78 J and the final internal energy is 180 J. He also knows that
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As we know by the first law of thermodynamics

Q = \Delta U + W

here we know that

Q = heat given to the system

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now we can say that heat will be given as

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now here we can say that Jin does the error in his first step while calculation of change in internal energy as he had to subtract it while he added the two energy

So best describe Jin's Error is

<em>B )For step 1, he should have subtracted 78 J from 180 J to find the change in internal energy. </em>

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3 years ago
Vectors A and B lie in the xy-plane. Vector A has a magnitude of 19.1 and is at an angle of 125.5º counterclockwise from the +x-
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3 years ago
A soccer player pumps air into a soccer ball until no more air can be pushed inside. Describe the air inside the soccer ball com
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Answer:

the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.

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This exercise asks to describe the inflation situation of a spherical fultball.

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