Answer: The correct answer is : A, B, C, D. All statements are correct.
Explanation: This case is called non-competitive inhibition. As a result of the inhibition of the enzyme, there will eventually be less substrate that becomes the final product and this route will be closed. Enzyme 1 has two binding sites.
idksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu j
Explanation:
A=b+d that is the way to rewrite the equation
Answer:
An electrical charge is created when electrons are transferred to or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.
Explanation:
plz Mark my answer in brainlist and follow me
Answer:
When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.
The corresponding relation for diffraction is
,
where
is the wavelength of light,
is the slit width, and
is the diffraction angle.
From this relation we clearly see that the diffraction angle
is directly proportional to the wavelength
of light—longer the wavelength larger the diffraction angle.