We have that for the Question "Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e" it can be said its equation is
From the question we are told
Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e
<h3>An Expression for the <em>magnitude </em>of charge moved</h3>Generally the equation for the <em>magnitude </em>of charge moved, Q is mathematically given as
Therefore
An expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e" it can be
For more information on this visit
Answer:
Emf induced in the coli will be equal to 26 volt
Explanation:
We have given number of turns N = 13
It is given that magnetic flux changes from 2.1 Weber to 2.7 Weber in 0.3 sec
Change in flux
Change in time dt = 0.3 sec
We have to find the induced emf
Induced emf is equal to
So emf induced in the coil will be equal to 6 volt
Answer:
the tension in each side of the cable is 3677.57 N
Explanation:
given data
traffic light = 20 kg
cable between two poles = 30 m
sag in the cable = 0.40 m
solution
by the free body diagram
tan θ = .............1
θ = 1.527 °
and
tension = mg
The net force is along x - axis is express as
T2 cosθ = T1 cosθ .................2
so T2 - T1 ..............3
and
when we take it along y axis that is express as
( T1 + T2) sinθ = mg ...................4
so by equation 3 we put here
2 × T1 sin(1.527) = 20 × 9.8
T1 = 3677.57 N
Answer:
7908.92307 W
683330953.248 J
Explanation:
k = Heat conduction coefficient = 0.8 W/(m·°C)
A = Area =
l = Thickness = 0.65 cm
= 24°C
= 0°C
Rate of heat transfer is given by
The rate of heat transfer is 7908.92307 W
Amount of energy is given by
The energy transferred through the window in one day is 683330953.248 J