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horsena [70]
3 years ago
14

13.3 × 17.9 What is the work?

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0
238.07777777777777777
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A recipe calls for 2 1/2cups of flour to make 18 muffins. If someone needs to make 2 1/2 times the recipe, how much flour should
ANTONII [103]

Answer:

l''kkk 1/2 cups

Step-by-step explanation:

8 0
3 years ago
I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit
makkiz [27]

Answer:

Possible answer: \displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6.

Step-by-step explanation:

Rewrite the bounds of c as fractions:

The simplest fraction for 1.5 is \displaystyle \frac{3}{2}. Write the upper bound 2 as a fraction with the same denominator:

\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}.

Hence the range for c would be:

\displaystyle \frac{3}{2} < c < \frac{4}{2}.

If the denominator of c is also 2, then the range for its numerator (call it p) would be 3 < p < 4. Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than 2.

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}.

\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}.

At this point, the difference between the numerators is now 2. That allows a number (7 in this case) to fit between the bounds. However, \displaystyle \frac{1}{c} = \frac{4}{7} can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}.

\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}.

\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}.

\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}.

\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}.

\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}.

It is important to note that some expressions for c can be simplified. For example, \displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5} because of the common factor 2.

Apparently \displaystyle c = \frac{16}{10} = \frac{8}{5} works. c = 1.6 while \displaystyle \frac{1}{c} = \frac{5}{8} = 0.625.

8 0
4 years ago
Read 2 more answers
How do u solve 4n-6=10n
Tcecarenko [31]

Answer:

n = -1

Step-by-step explanation:

4n - 6 = 10n

Combine like terms: (you can see that both 4n and 10n both have a n. This means that they are like terms. You would just add/subtract them as usual)

4n - 10n = 6

-6n = 6

n = -1

5 0
3 years ago
Read 2 more answers
Help,anyone can help me do quetion.​
swat32

Answer:

Step-by-step explanation:

The given figure is parallelogram becasue their opposite sides are equal.

68+45+30+x=180 degree (sum of adjacent sides of a parallelogram are equal)

143 +x=180

x=180-143

x=37 degree

y=45 degree

4 0
3 years ago
The average hourly wage for a high school student in Illinois is $8.25 per hour with a standard deviation of $.25. Assume hourly
serious [3.7K]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: hourly wage of a high school student

X~N(μ;σ²)

X[bar]= $8.25

σ= $0.25

For a 95% CI for the average hourly wage for<u> 1 </u>high school student:

For this exercise you have to consider the sample size n=1

a) The margin of error of the CI is calculated as:

d= Z_{1-\alpha /2} * σ

1-α: 0.95 ⇒ α:0.05

1-α/2:0.975

Z_{1-\alpha /2}= Z_{0.975}= 1.96

d= 1.96 * 0.25= 0.49

b)

The formula for the interval is

X[bar] ± Z_{1-\alpha /2} * σ

[8.25 ± 0.49]

[7.76; 8.74]

With a 95% you'd expect the interval $[7.76; 8.74] to include the average hourly wage of one high school student in Illinois.

c)

Te calculated interval is $ [7.76; 8.74] the value $9.15 does nor fall within that acceptable range.

I hope this helps!

7 0
3 years ago
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