1B: -3(9x-q)
-27x + 3q
Step 1: Distribute the -3 to the 9x to get -27x.
Step 2: Distribute the -3 to the -q.
2B: 2(12+5p)
24 + 10p
Step 1: Distribute the 2 to the 12 to get 24.
Step 2: Distribute the 2 to the 5p to get 10p.
3B: -7(-8y+7)
56y - 49
Step 1: Distribute the -7 to the -8y to get 56y.
Step 2: Distribute the -7 to the 7 to get -49.
4B: 10(2+7c)
20 + 70c
Step 1: Distribute the 10 to the 2 to get 20.
Step 2: Distribute the 10 to the 7c to get 70c.
5B: -8(7+11k)
-56 - 88k
Step 1: Distribute the -8 to the 7 to get -56.
Step 2: Distribute the -8 to the 11k to get -88k.
6B: -(3-7u)
-1(3-7u)
-3 + 7u
Step 1: Place a 1 after the negative symbol to symbolize -1.
Step 2: Distribute the -1 to the three to get -3.
Step 3: Distribute the -1 to the -7u to get 7u.
7B: -6(5p + s)
-30p - 6s
Step 1: Distribute the -6 to the 5p to get -30p.
Step 2: Distribute the -6 to the s to get -6s.
:) :D
Answer: 15
Step-by-step explanation:
From the question, we can infer from the information given that:
5 eclaires boxes = 1 free eclaires box.
Therefore, to get the number of eclaires boxes that the kids will get if they bring 77 eclaires boxes, we have to divide 77 by 5 and this will be:
= 77 / 5
= 15.4
= 15
The group of kids will receive 15 free boxes
<span> log3x − 5 16 = 2
+516 +516
log3x=518
x=(10^518)/3
the answer seems a bit crazy, you probably typed something wrong</span>
The equation has one solution, x = -7.
