Answer:
RS = 20
ST = 40
Step-by-step explanation:
R____S____T
RS + ST = RT
3x - 16 + 4x - 8 = 60
3x + 4x - 16 - 8 = 60
7x - 24 = 60
+24 +24
--------------------------------
7x = 84
/7 /7
---------------------------------
x = 12
Let's use what we got for x to find the length of ST and RS
ST = 4x - 8
= 4(12) - 8
= 48 - 8
ST = 40
RS = 3x - 16
= 3(12) - 16
= 36 - 16
RS = 20
so, RS = 20, ST = 40, and RT = 60
I think it is
(1/3)+1+3+9+27+81+243
=364/1/3
=1093/3
Step-by-step explanation:
As the vertex (−2,5) and focus (−2,6) share same abscissa i.e. −2, parabola has axis of symmetry as x=−2 or x+2=0
Hence, equation of parabola is of the type (y−k)=a(x−h)2, where (h,k) is vertex. Its focus then is (h,k+14a)
As vertex is given to be (−2,5), the equation of parabola is
y−5=a(x+2)2
as vertex is (−2,5) and parabola passes through vertex.
and its focus is (−2,5+14a)
Therefore 5+14a=6 or 14a=1 i.e. a=14
and equation of parabola is y−5=14(x+2)2
or 4y−20=(x+2)2=x2+4x+4
or 4y=x2+4x+24
Answer:
After 1.5 second of throwing the ball will reach a maximum height of 44 ft.
Step-by-step explanation:
The height in feet of a ball after t seconds of throwing is given by the function
h = - 16t² + 48t + 8 .......... (1)
Now, condition for maximum height is
{Differentiating equation (1) with respect to t}
⇒ 
seconds.
Now, from equation (1) we get
h(max) = - 16(1.5)² + 48(1.5) + 8 = 44 ft.
Therefore, after 1.5 seconds of throwing the ball will reach a maximum height of 44 ft. (Answer)
