I didn't get all the part with the tiles, but here's the general answer:
given a polynomial
![p(x)=ax^2+bx+c](https://tex.z-dn.net/?f=p%28x%29%3Dax%5E2%2Bbx%2Bc)
we have that
is a factor of
if and only if k is a root of
, i.e. if
![p(k)=ak^2+bk+c=0](https://tex.z-dn.net/?f=p%28k%29%3Dak%5E2%2Bbk%2Bc%3D0)
So, given the polynomial
![p(x)=x^2-9x+14](https://tex.z-dn.net/?f=p%28x%29%3Dx%5E2-9x%2B14)
We can check if
is a factor by evaluating
:
![p(9)=81-81+14=14\neq 0](https://tex.z-dn.net/?f=p%289%29%3D81-81%2B14%3D14%5Cneq%200)
So,
is not a factor.
Similarly, we can evaluate
to check if
are factors:
![p(2)=4-18+14=0,\quad p(-5)=25+45+14=84\neq 0,\quad p(-7)=49+63+14=126 \neq 0](https://tex.z-dn.net/?f=p%282%29%3D4-18%2B14%3D0%2C%5Cquad%20p%28-5%29%3D25%2B45%2B14%3D84%5Cneq%200%2C%5Cquad%20p%28-7%29%3D49%2B63%2B14%3D126%20%5Cneq%200)
So, only
is a factor of ![x^2-9x+14](https://tex.z-dn.net/?f=x%5E2-9x%2B14)
Answer:
2π
Step-by-step explanation:
Area = πr^2
= π2^2
= 4π
4π is the area of the whole circle, so divide it in half to get the semicircle.
<u>= 2π</u>
Answer: They all = 0 How?
Step-by-step explanation:
Anything in mulitplcation that is times by 0 will always equal to zero.
5^10X0 = 0
10^5X0 = 0
- R3KTFORGOOD ☕
Answer:4
Step-by-step explanation: 3x+1−2x=2x+5−2x
x + 1 = 5
x+1−1=5−1
x=4