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4 years ago

Is a rectangle always a parallelogram? Yes or No

Mathematics

2 answers:

mezya [45]4 years ago

8 0

The answer is yes.

Rectangles are quadrilaterals with four right angles. It can also be defined as an equiangular quadrilateral, since equiangular means that all of its angles are equal.

raketka [301]4 years ago

3 0

Yes, a rectangle is always a parallelogram.

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Order the numbers from least to greatest.<br><br> 1.25, 11, -0.41, -0.41111..., -16, 3/7

Zepler [3.9K]

Answer:

$- 16 < - 0.41111... < -0.41 < \frac{3}{7} < 1.25 < 11$

Step-by-step explanation:

$\frac{3}{7} = 3 \div 7 = 0.428...$

5 0

3 years ago

2. In Australia, there are approximately 100 species of venomous snakes, but only about 12 have a deadly

Savatey [412]

Answer:

The required probability is 0.3717.

Step-by-step explanation:

Consider the provided information.

There are approximately 100 species of venomous snakes, but only about 12 have a deadly bite.

zoo randomly selects one snake from each of five different species to show visitors.

The total number of ways to select 5 different species out of 100 are:

$^{100}C_5=\frac{100!}{5!95!}=75287520$

We need to find the probability that exactly one of the five snakes shown is deadly.

That means out of 12 deadly bite we need to select only 1.

Thus, the number of ways are:

$^{12}C_1\times ^{88}C_4=\frac{12!}{11!}\cdot\frac{88!}{4!84!}=27982680$

Hence, the required probability is:

$\frac{27982680}{75287520}\approx0.3717$

The required probability is 0.3717.

4 0

3 years ago

What is 0.57 x 1000<br> How do I solve this

Temka [501]

570 is the answer. since 1000 has 3 zeroes on the end of it, you take the decimal point and move it 3 spots to the right.

5 0

4 years ago

In a standard deck of cards, P(heart)

g100num [7]

Answer:

13/52 (0.25) (25%)

Explanation:

There are 52 cards in a standard deck and there are four suits.

52/4 = 13

So, the probability (assuming that’s what you are asking for) is a 13/52 chance you will pull a hearts card.

5 0

3 years ago

Read 2 more answers

Divide x ^ 4 + x - 1 by x - 1

vladimir2022 [97]

The required, divide is given by $=x^3+x^2+x+2+\frac{1}{x-1}$