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3 years ago

Solve for y. -80 y = 80

Mathematics

2 answers:

tekilochka [14]3 years ago

8 0

-1, because a negative times a negative is a positive

FrozenT [24]3 years ago

6 0

-80y=80
-80y/-80=80/-80
Y = -1 Hope this helped!

-Twix

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Enter your answer and show all the steps that you use to solve this problem in the space provided.

Greeley [361]

Answer:

The steps are below. Thanks.

Step-by-step explanation:

Equation= 0.6(1)+0.8=1.4

1. Calculate the product. Any expression multiplied by 1 remains the same.

0.6×1+0.8 to 0.6+0.8

2. Calculate. Add the numbers.

0.6+0.8 to 1.4

3. Answer found!

Alternative Form of the final answer 1.4 could be: 7/5 or 1 2/5.

Hope this helps and if you could mark me as brainliest. Thanks!

7 0

2 years ago

A certain standardized test's math scores have a bell-shaped distribution with a mean of 530 and a standard deviation of 119. Co

kumpel [21]

Answer:

a) 68.2%

b) 31.8%

c) 2.3%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 530

Standard Deviation, σ = 119

We are given that the distribution of math scores is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(test scores is between 411 and 649)

$P(411 \leq x \leq 649)\\\\= P(\displaystyle\frac{411 - 530}{119} \leq z \leq \displaystyle\frac{649-530}{119})\\\\= P(-1 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -1)\\= 0.841 - 0.159 = 0.682 = 68.2\%$

b) P(scores is less than 411 or greater than 649)

$P(x < 411 < x, x > 649)\\=1 = P(411 \leq x \leq 649)\\=1 - 0.682\\=0.318 = 31.8\%$

c) P(score greater than 768)

P(x > 768)

$P( x > 768) = P( z > \displaystyle\frac{768 - 530}{119}) = P(z > 2)$

$= 1 - P(z \leq 2)$

Calculation the value from standard normal z table, we have,

$P(x > 768) = 1 -0.977 = 0.023 = 2.3\%$

5 0

3 years ago

Combine like terms to create an equivalent expression -4/7p+(-2/7p)+1/7

STatiana [176]

-6/7p+1/7 um Idk what you wanted me to do but I added -4/7p with -2/7p

7 0

3 years ago

Read 2 more answers

A surveyor has poles A, B, and C set to form a right triangle with the right angle at B. If the distance from A to B is 35 meter

tia_tia [17]

A^2+b^2=c^2
35^2+25^2=25^2
So the answer is 25

6 0

3 years ago

Find the length of the missing side. triangle with an 8 inch side and 12 inch side with a right angle 8.9 in. 104 in. 4 in 14.4

Mamont248 [21]

Given:

In a triangle, length of one side is 8 inches and length of another side is 12 inches, and an angle is a right angle.

To find:

The length of the missing side.

Solution:

In a right angle triangle,

$Hypotenuse^2=Perpendicular^2+Base^2$

Suppose the measures of sides adjacent to the right angle are 8 inches and 12 inches.

Substituting Perpendicular = 8 inches and Base = 12 inches, we get

$Hypotenuse^2=8^2+12^2$

$Hypotenuse^2=64+144$

$Hypotenuse^2=208$

Taking square root on both sides, we get

$Hypotenuse=\sqrt{208}$

$Hypotenuse=14.422205$

$Hypotenuse\approx 14.4$

The length of the missing side is 14.4 inches. Therefore, the correct option is D.

4 0

2 years ago