Answer:
answer is b!
Step-by-step explanation:
hope this helps!!!
Answer: A hexagon has 6 lines of symmetry.
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Well, accordingly to the graph, it has a positive slope so we can eliminate b and d. So it is either a or c. As x increases, so does y. Y is almost not quite equal to 3x-2. In fact, it is greater, so I'd go with A. I'm pretty confident.
It is given that the triangle is isosceles right triangle . And in an isosceles right triangle the legs are equal . Let each leg be of x units. Now we use pythagorean identity, which is
So the length of each leg is 
