Answer:
91/216
Step-by-step explanation:
The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.
P(at least one 4) = 1 − P(no 4s)
P(at least one 4) = 1 − (5/6)³
P(at least one 4) = 91/216
Alternatively, you can calculate it this way.
The probability of getting a 4 on the first roll is 1/6.
The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.
The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.
The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.
Hey There!
as a mixed number would be
Thank You!
Answer:
(3×6) -1+4
18+3
21 is your answer ☺️. If I'm right so,
Please mark me as brainliest. thanks!!!
Answer:
60 and 25
Step-by-step explanation:
The range is the difference between the maximum value and the minimum value.
maximum value = 125, minimum value = 65
range = 125 - 65 = 60
------------------------------------------
The interquartile range is the difference between the upper quartile Q₃ and the lower quartile Q₁
Q₃ is the value at the right side of the box = 115
Q₁ is the value at the left side of the box = 90
interquartile range = 115 - 90 = 25
Answer:
(a) 
0.32
(b) 0.68
Step-by-step explanation:
It is given that a binomial experiment is carried out.
n = 4 trials
Probability of success, p = 0.25
We know that in a binomial experiment:
Probability of success + Probability of failure = 1
p + q = 1
So, q = 1 - 0.25 = 0.75
Probability of 'r' number of successes in 'n' trials of a binomial experiment is given as:
(a) P(r = 0) = ?
Putting values of x = 0, p and q:
(b) Find P(r ≥ 1) = ?
<em>Using complement rule:</em>
<em>P(r =0 ) + P(r ≥ 1) = 1</em>
0.32 + P(r ≥ 1) = 1
P(r ≥ 1) = 1 - 0.32
P(r ≥ 1) = 0.68
So, the answer are:
(a) 0.32
(b) 0.68
