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bonufazy [111]
3 years ago
6

Please please please heelp

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0

Answer: y=|3(x+2)| = |3x+6|

You may want to verify that the points shown on the graphs indeed satisfy the above equation:

(-3,3): 3=|3(-3)+6|=3   (True)

(-2,0): 0=|3(-2)+6|=0 (True)

(-1,3): 3=|3(-1)+6|=3 (True)

This confirms the equation above is correct.

Anastasy [175]3 years ago
4 0

y=3|3+2|

Hope this helps!

-Payshence

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Can I see how long division works on these? pls no sketchy links
alexandr1967 [171]

Answer:

Step-by-step explanation:

11) First write in decreasing exponential terms and fill in blanks with zeros.

Our goal is to eliminate all term in the dividend by subtraction

          ________________

2v - 2 |  2v³ - 16v² + 0v + 13

we see that 2v needs to be multiplied by 1v² to eliminate the first term

          <u>              v²                </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v²

multiply your estimate by your divisor and subtract from the dividend.

bring down the next term and repeat.

          <u>              v²    -7v       </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v

repeat again

<u />

          <u>              v²  -  7v  -  7 </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v + 13

                            <u>-(-14v + 14)</u>

                                          -1

and remainder gets put over the divisor and appended

v²  -  7v  -  7 - 1/(2v - 2)

13) Same process

          <u>                                      </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>              8a²                 </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

          <u>              8a² -    4a     </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                   -(-<u>20a² -   4a)</u>

                                -35a - 5

          <u>              8a² -    4a  - 7  </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                    -(<u>20a² -   4a)</u>

                                -35a - 5

                              -<u>(-35a - 7)</u>

                                           2

8a² - 4a - 7 + 2/(5a + 1)

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3 years ago
What is the area of the figure?
iren [92.7K]

Answer:

3600

Step-by-step explanation:

5 0
3 years ago
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When i convert the percentages from a 360° pie chart do the percentages total to 100% or 360%?
Andrej [43]

Answer:

Step-by-step explanation:

100%

8 0
3 years ago
Point M is the midpoint of AB. If the coordinates of M are (2,8) and the coordinates of A are (10,12),what are the coordinates o
ElenaW [278]

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{10}~,~\stackrel{y_1}{12})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ x + 10}{2}~~~ ,~~~ \cfrac{ y + 12}{2} \right)~~=~~\stackrel{M}{(2,8)}\implies \begin{cases} \cfrac{x+10}{2}=2\\[1em] x+10=4\\ \boxed{x=-6}\\[-0.5em] \hrulefill\\ \cfrac{y+12}{2}=8\\[1em] y+12=16\\ \boxed{y=4} \end{cases}

4 0
3 years ago
What is the answer to the questions​
loris [4]
<h3>Answer:  x = 40</h3>

===================================================

Work Shown:

A+B+C = 180 ..... three angles of any triangle add to 180

(2x+10)+(x)+(2x-30) = 180

5x-20 = 180

5x = 180+20 .... adding 20 to both sides

5x = 200

x = 200/5 ... dividing both sides by 5

x = 40

This is the measure of angle B

We can stop here.

If you need to know the values of the other angles, then,

  • angle A = 2x+10 = 2*40+10 = 90
  • angle C = 2x-30 = 2*40-30 = 50

Then note how A+B+C = 90+40+50 = 90+90 = 180 which helps confirm our answer.

7 0
2 years ago
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