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kondaur [170]
3 years ago
14

How do i solve equations by substitution?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0
Just doing one! Here's my problem:    x-y-11  x-3y=1

So when you subsitute everything it should look like this: 1y-11-3y=1 (There needs to be a one in front of the y because it's just always been there. they don't always put it in the eqation.)  You need to + the 11 and you have to do that to each side. So... 1y-11-3=1
                                                                                                                +11    +11
Now it should look like this: 1y-3y=12
Combine the 1y and -3y to get -4y=12      Last step is divide -4y and 12 by 4  . Answer is y=3
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Identify the function as a growth or decay function. y = (1/2)x
tangare [24]

Answer:

This would be a decay function.

Step-by-step explanation:

When a function is a growth function that means that it is growing but a decay function means that it is getting smaller.

8 0
3 years ago
Solve the equation algebraically for all values of X
noname [10]
This is a problem you need to solve using logs. When you use logs you can "pull" the exponents down in front of the log to get a new equation that looks like this: 2x^3 + x^2 log 81 = 6x - 3 log 27. Now divide both sides by log 81 and 6x - 3 simultaneously to get (2x^3 + x^2)/(6x - 3) = (log 27)/(log 81). If you do the log math on the right side you get .75. Now multiply both sides by 6x-3 to get 2x^3+x^2 = .75(6x-3). If you distribute that out on the left side you'll get 2x^3+x^2=4.5x-2.25. Now move everything over to the left side and set the whole thing equal to 0: 2x^3+x^2-4.5x+2.25=0. When you solve for x, you are in essence factoring, so do this by grouping: x^2(2x+1)-2.25(2x+1). Now finally factor out the 2x+1 to get (2x+1)(x^2-2.25). You're not done yet though cuz you need to solve each of those for x: 2x+1=0, and x= -1/2; x^2=2.25, and x=+/- 1.5. So all the values for x here are -1/2, 1.5, and -1.5

5 0
3 years ago
X^4 a^5 / x^3 a^3<br><br> answers<br><br> x^2 a^2<br> xa^2<br> x^-1 a^-2<br> a^2/x
bagirrra123 [75]
Well the answer i got was a^{8}x when i multiplied
the answer i got when i added was x^{4} + \frac{ a^{5} }{ x^{3} } + a^{3}
3 0
3 years ago
A small company plans to invest in a new advertising campaign. There is a 20% chance that the company will lose $5,000, a 50% ch
Viktor [21]

A small company plans to invest in a new advertising campaign.

There is a 20% chance that the company will lose $5,000 ,

50% chance of a break even, and a 30% chance of a $10,000 profit


So the expected value from the advertisement campaign is calculated as - 20% of 5000 + 0% of 5000 + 30% of 10,000

= -1000 + 0 + 3000

= 2000


The expected value from the advertisement campaign is $2000.

So the Company must go ahead with the campaign.


Answer : Option A


Hope it helps.


Thank you ..!!

3 0
3 years ago
Dan has 3 ⅔ cups of milk. If he used ¼ of the milk for his breakfast, how much milk does Dan have left?
riadik2000 [5.3K]

There would be 3 2/12 left.

2/3 x 1/4 = 2/12

Hope this helps!

Sorryyyy :C

6 0
3 years ago
Read 2 more answers
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