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stepladder [879]
3 years ago
7

How do I solve 3a=57

Mathematics
2 answers:
Kazeer [188]3 years ago
7 0
You have to do the reverse operation to 57 so you have to do 57÷3 which is 19
MatroZZZ [7]3 years ago
6 0
Divide 3 from both sides to get a=57/3 then a=19
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Answer:

A

Step-by-step explanation:

this is true due to the ratio of a 30-60-90 triangle, which is 1-2-sqrt(3). The 12 corresponds to the sqrt(3), which means that the 1 corresponds to 4sqrt3 and the 2 to 8sqrt3.

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What is the width of heng’s area model??
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2x + 1

Step-by-step explanation:

Well you can get side for the left shape is 2x

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Evaluate g(p)h(p) by modeling or by using the distributive property.
lana66690 [7]

Answer:

g(p)h(p) = = p^4 + 2p^3 - 8p^2 -2p + 4

Step-by-step explanation:

Hello!

We will use the distributive property:

g(p) h(p) = ( p - 2 ) * ( p^3 + 4p^2 - 2 ) = ( p^3 + 4p^2 - 2 ) * ( p - 2 )

The distributive property allow us to multiply the first term <em>(p^3 + 4p^2 - 2) </em>by every member of the second member, that is <em>p </em>and <em>-2.</em>

g(p) h(p) = ( p^3 + 4p^2 - 2 ) * p + ( p^3 + 4p^2 - 2 ) * (-2)

Now we can do the same for the two resulting terms, that is, we can multiply every term in parenthesis<em> ( p^3 + 4p^2 - 2 ) </em>by the term on the rigth:

( p^3 + 4p^2 - 2 ) * p = (p^3)*p + (4p^2)*p - 2*p = p^4 + 4p^3 -2p

( p^3 + 4p^2 - 2 ) * (-2) = (p^3)*(-2) + (4p^2)*(-2)- 2*(-2) = -2p^3 - 8p^2 + 4

And now we can sum both terms and add monomials with the same exponent of t. Look at the underlined terms

g(p) h(p) = p^4 + <em><u>4p^3</u></em><em> </em>-2p - <u>2p^3 </u>- 8p^2 + 4 = p^4 +<em><u>2p^3</u></em> -2p - 8p^2 + 4

              = p^4 + 2p^3 - 8p^2 -2p + 4

3 0
3 years ago
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