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ANEK [815]
2 years ago
14

Sketch the graph of y=2(x+1)^2 and identify the axis of symmetry.

Mathematics
2 answers:
CaHeK987 [17]2 years ago
6 0

The axis of symmetry is (-1,0)


Hope this helps!

Evgen [1.6K]2 years ago
6 0

The axis of symmetry of this equation is at -1.


We can determine this in any equation in vertex form just by looking at it. Firstly, start with the base form of vertex form.


y = (x - h)^2 + k


In this equation (h, k) is the vertex. Working by this fact, we know the vertex is (-1, 0). The axis of symmetry is always the x value of the vertex, which allows us to state the vertex at x = -1.

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Answer:

\huge\boxed{y=-\dfrac{1}{4}x-1\to x+4y=-4}

Step-by-step explanation:

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\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (8,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}

x=8,\ y=-3\\\\-3=-\dfrac{1}{4}(8)+b\\\\-3=-2+b\qquad\text{add 2 to both sides}\\\\-1=b\to b=-1

\text{Therefore the equation is:}\ y=-\dfrac{1}{4}x-1.\\\\\text{Convert to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4y=-x-4\qquad\text{add}\ x\ \text{to both sides}\\\\x+4y=-4

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Answer:

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Step-by-step explanation:

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