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denis23 [38]
2 years ago
12

How do you factor trinomials? How can we check the binomial factors to verify that they are truly factors? Create an example of

a trinomial and factor it to its binomial factors.
Mathematics
1 answer:
Travka [436]2 years ago
3 0

Answer:

See the step-by-step

Step-by-step explanation:

How do you factor trinomials? -

You factor trinomials by using methods like FOIL multiplication and simple factoring patterns.

How can we check the binomial factors to verify that they are truly factors?

We can multiply the binomial factors out to see that they are truly factors.

Create an example of a trinomial and factor it to its binomial factors.

x^{2}+5x+6 factors into

(x+2)(x+3).

Sorry for the trashy answer.

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A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
You put $300 in the bank of warmerdam and onto $44 in interest. What was the percent interest rate? Round to the nearest percent
Ludmilka [50]
Approximately 15% interest rate
3 0
2 years ago
Write each pair of quantities as a unit rate.
Ronch [10]
A) 75heartbeats per min
B) $9.35 per ticket
C) 2.25 per golf ball
D) $9.75 per hour
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2 years ago
A student wants to survey the sophomore class of 200 students about whether the school should require uniforms. A
Fittoniya [83]

Answer: C

Step-by-step explanation:

<u>Given:</u>

Sample size (n) = 50

x = 12

\widehat{\mathbf{p}}=\frac{\mathbf{x}}{n}=\frac{12}{50}=0.24

Confidence level = 90%

α = 1 − 0.90 = 0.10

α/2 = 0.05

\text { Critical value }\left(z_{c}\right)=z_{\frac{\alpha}{2}}=z_{0.05}=1.6449

(from standard normal table)

90% Confidence interval is,

\begin{aligned}&\text { Confidence interval }=\widehat{\mathbf{p}} \pm z_{c} \times \sqrt{\frac{\hat{\mathbf{p}}(1-\hat{\mathbf{p}})}{n}} \\&\text { C. I }=0.24 \pm 1.6449 \times \sqrt{\frac{0.24(1-0.24)}{50}} \\&\text { C. I }=0.24 \pm 1.65 \times \sqrt{\frac{0.24(1-0.24)}{50}}\left\end{aligned}

Therefore, 90% confidence interval for the true proportion of sophomores who favour the adoption of uniforms is C

6 0
2 years ago
Which number is bigger 25% or 0.025
kenny6666 [7]

50%

The website told me

3 0
2 years ago
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