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Viefleur [7K]
3 years ago
9

A total of 316 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t

ickets sold was three times the number of adult tickets sold. How many adult tickets were sold?
Mathematics
1 answer:
Olenka [21]3 years ago
7 0

Answer:

52.5 adult tickets

52 rounded

Step-by-step explanation:

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If f x = 7x<br><br> 2 − 4x − 10, then f −3 =?
Schach [20]

Answer:

f(x)=xy3 -4xy2 -7x+10

Step-by-step explanation:

the xy3 and xy2 means x to the 3rd power and x to the second power

7 0
3 years ago
What is the solution of 9|2x – 1| + 4 &lt; 49?
luda_lava [24]

Answer: -2

Step-by-step explanation:

You need to set up two cases (Positive case and negative case) and solve for "x".

- POSITIVE CASE IF: 2x-1>0

9(2x -1) + 4 < 49\\18x-9

- NEGATIVE CASE IF: 2x-1

-9(2x -1) + 4 < 49\\-18x+9

Therefore, the solution is:

-2

3 0
3 years ago
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Write a multiplication fact that goes with this division fact.<br><br> 24 ÷ 4 = 6
Andrew [12]

4 x 6 = 24 six times four is twenty four

8 0
4 years ago
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The measure of an angle is 164°. What is the measure of its supplementary angle?
storchak [24]

Answer:

16

Step-by-step explanation:

180-164=16 do the answer is 16

3 0
2 years ago
In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x
Alexus [3.1K]

Answer:

Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

Step-by-step explanation:

Given Differential Equation,

y"-2y'+y=xe^x ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

\implies\:y(x)=y_c(x)+y_p(x)

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

y_c(x)=C_1e^x+c_2xe^x

Now for particular solution,

let y_p(x)=Ax^3e^x

y'=Ax^3e^x+3Ax^2e^x

y"=Ax^3e^x+6Ax^2e^x+6Axe^x

Now putting these values in (1), we get

Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x

Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x

6Axe^x=xe^x

6A=1

A=\frac{1}{6}

\implies\:y_p(x)=\frac{x^3e^x}{6}

Therefore, Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

8 0
4 years ago
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