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3 years ago

9

A total of 316 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t

ickets sold was three times the number of adult tickets sold. How many adult tickets were sold?

1 answer:

Olenka [21]3 years ago

7 0

Answer:

52.5 adult tickets

52 rounded

Step-by-step explanation:

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Solve the system of equations.

Brums [2.3K]

Solve the system of equations.
12x + 3y = 12
-6x +y = -26

A) (-3,9)
B (-6, -9)
© (-3,8)
D (3, -8)

12x + 3y = 12
2(-6x +y = -26)

12x + 3y = 12
-12x + 2y = -52

—-now x cancels out

5y/5 = -40/5

y = -8

The answer should be D. Let me know if you got it right.

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2 years ago

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Semmy [17]

Answer:

Step-by-step explanation:

when a rotation of 180 ° happens, it switches the (x,y) coordinates from (x,y) to (-x,-y) .. that's alll... soo for M then, of (3,4) it switches to M ' = ( -3, -4) see?

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3 years ago

*NO 194 39% 13:08 Pilih jawaban yang paling tepat Segitiga PQR dan segitiga XYZ 5 poin merupakan dua segitiga yang kongruen. Bes

Illusion [34]

Answer:

Option d. PQ = YZ

Step-by-step explanation:

<u><em>The question in English is</em></u>

Choose the most appropriate answer. The PQR triangle and the XYZ triangle are two congruent triangles. The angle P = the angle Y and PR = YX. Side pairs of the same length are ... a. PQ = XZ b. QR = YZ c. QR = XY d. PQ = YZ

we know that

If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent

Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement

so

we have that

$m\angle P=m\angle Y$

$PR=YX$

so

Triangle PQR is congruent with Triangle YZX

That means

<em><u>Corresponding angles</u></em>

$m\angle P=m\angle Y$

$m\angle Q=m\angle Z$

$m\angle R=m\angle X$

<u><em>Corresponding sides</em></u>

$PQ=YZ\\QR=ZX\\PR=YX$

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3 years ago

Factor the following quadratic function (put the lesser value first).<br> x2 + 5x + 6

Anestetic [448]

Answer: Evaluate

$5x+x_{2} +6$

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2 years ago

A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei

ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is $576\ cm^{3}$

Part 2) The total surface area of the paperweight is $400\ cm^{2}$

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the square base

H is the height of the pyramid

$B=8^{2}=64\ cm^{2}$

$H=3\ cm$

substitute

$V=\frac{1}{3}(64)(3)=64\ cm^{3}$

step 2

Find the volume of the cube

The volume of the cube is equal to

$V=b^{3}$

$V=8^{3}=512\ cm^{3}$

step 3

Find the volume of the paperweight

$64\ cm^{3}+512\ cm^{3}=576\ cm^{3}$

Part 2) what is the total surface area of the paperweight?

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

$SA=5b^{2}$

$SA=5(8^{2})=320\ cm^{2}$

step 2

Find the lateral area of the pyramid

$LA=4[\frac{1}{2}bh]$

$LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}$

step 3

Find the total surface area of the paperweight

$320\ cm^{2}+80\ cm^{2}=400\ cm^{2}$

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3 years ago