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Komok [63]
3 years ago
9

Drag the tiles to the correct boxes to complete the pairs.

Mathematics
1 answer:
Elis [28]3 years ago
6 0

Answer:

Each part is solved and working is shown  

Step-by-step explanation:

1)

-6\displaystyle\frac{4}{9}-3\displaystyle\frac{2}{9}-8\displaystyle\frac{2}{9}\\\\= -\displaystyle\frac{58}{9}-\displaystyle\frac{29}{9}-\displaystyle\frac{74}{9}\\\\= -\displaystyle\frac{161}{9}\\=-17\displaystyle\frac{8}{9}

2)

-12.48-(-2.99) -5.62\\=-12.48 + 2.99 -5.62 \\=-15.11

3)

-19\displaystyle\frac{2}{9}-4\displaystyle\frac{1}{9}+3\displaystyle\frac{4}{9}\\\\= -\displaystyle\frac{173}{9}-\displaystyle\frac{37}{9}+\displaystyle\frac{31}{9}\\\\= -\displaystyle\frac{179}{9}\\=-19\displaystyle\frac{8}{9}

4)

-353.92 - (-283.56) - 131.29\\= -353.92 + 283.56 - 131.29\\= -201.65

5)

83\displaystyle\frac{1}{5}-108\displaystyle\frac{2}{5} + 99\displaystyle\frac{1}{5}\\\\= \displaystyle\frac{416}{5}-\displaystyle\frac{542}{5}+\displaystyle\frac{496}{5}\\\\= -\displaystyle\frac{370}{5}\\= 74

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if a square + b square + c square minus ab minus bc minus ca equals to zero, prove that A equals to B equal to C
lawyer [7]
A^2 + b^2 + c^2  - ab - bc - ca = 0
a.a + b.b + c.c = a.b + b.c + c.a

equating  term by term:- 
a = b
b = c 
c = a

Therefore a = b = c 
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3 years ago
Write <br> 25<br> 2<br> as a mixed number. <br> Give your answer in its simplest form.
masha68 [24]

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12 and 1/2<u>
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Step-by-step explanation:

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3 years ago
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Can someone pls pls PLS, help me out? ASAP!! (Geometry)<br> “Complete the proof”
Maru [420]

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2 years ago
WILL MARK BRAINLIEST
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Answer:

Part 1:

The solution set of the system of equations is x = 1, y = 1

Part 2:

The solution set is x = 1, y = 1

Part 3:

The similarity of the system of equations in Parts 1 and 2 is that they have the same solution set

The difference of the system of equations in Parts 1 and 2 is that they are arranged differently

Step-by-step explanation:

Part 1:

The system of equation is given as follows;

2·x + y = 3...(1)

x = 2·y - 1...(2)

The above system of equations can be written in terms of the variable, y, as follows;

For equation (1), we have;

y = 3 - 2·x

For equation (2), we have;

y = (x + 1)/2

From the attached graph created with Microsoft Excel, we have;

The solution set (the point of intersection) of the system of equations is x = 1, y = 1

To accurately find the common solution, we have;

(x + 1)/2 = 3 - 2·x

x + 1 = 2·(3 - 2·x) = 6 - 4·x

x + 1 = 6 - 4·x

x + 4·x = 6 - 1

5·x = 5

x = 5/5 = 1

x = 1

Therefore, y = 3 - 2·x = 3 - 2× 1 = 1, at the common solution

Part 2:

y = -2x + 3

x - 2y = -1

∴ x = 2y -1

y = -2(2y -1) + 3

y = -4y + 2 + 3

5y = 5

y = 1

x = 2y - 1 = 2 - 1 = 1

x = 1

The solution set is x = 1, y = 1

Part 3

The system of equations are similar in terms of their solution

The system of equations are different in terms of their arrangement

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2 years ago
Please help me with this
alexandr1967 [171]
Photo has the answer

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2 years ago
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