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3 years ago

8

The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inche

s.
Two students are told that the perimeter of this rectangle is at least 30 inches. The first student says, "The length of the long side must be at least 13 inches". The second student says, "The unknown number must be at least 10 inches". Which of the following statements is true?
a. The first student is correct.
b. Both students are correct.
c. Neither student is correct.
d. The second student is correct.

1 answer:

joja [24]3 years ago

8 0

Answer: The first student is correct

Step-by-step explanation:

If the length of rectangle is x-30=3-z then it must be true that 13 could be one of the answers

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What is the value of x that makes l1||l2? <br><br> A. 14<br> B. 11.6<br> C. 10<br> D. 26.7

stich3 [128]

Answer:

10

Step-by-step explanation:

By the alternate interior angles theorem,

$4x=2x+20 \\ \\ 2x=20 \\ \\ x=10$

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2 years ago

Please answer this I don't understand how to do it thanks

Mars2501 [29]

Answer:

The answer is 8.6×10¹⁴

Step-by-step explanation:

You can evaluate it :

$(4.3 \times {10}^{8} ) \times (2.0 \times {10}^{6} )$

$= (4.3 \times 2.0) \times ( {10}^{8} \times {10}^{6} )$

$= 8.6 \times {10}^{8 + 6}$

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6 0

3 years ago

Read 2 more answers

: Find the approximate perimeter of the isosceles triangle A OPD.

AleksAgata [21]

Answer:

24.98 units

Step-by-step explanation:

The picture of the question in the attached figure

we have the coordinates

P(1,-6),D(4,3),O(7,-6)

The perimeter of triangle OPD is equal to

$P=OP+PD+OD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance OP

we have

O(7,-6),P(1,-6)

substitute in the formula

$d=\sqrt{(-6+6)^{2}+(1-7)^{2}}$

$d=\sqrt{(0)^{2}+(-6)^{2}}$

$d_O_P=6\ units$

step 2

Find the distance PD

we have

P(1,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-1)^{2}}$

$d=\sqrt{(9)^{2}+(3)^{2}}$

$d_P_D=\sqrt{90}\ units$

step 3

Find the distance OD

we have

O(7,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-7)^{2}}$

$d=\sqrt{(9)^{2}+(-3)^{2}}$

$d_O_D=\sqrt{90}\ units$

step 4

Find the perimeter

$P=6+\sqrt{90}+\sqrt{90}$

$P=6+9.49+9.49=24.98\ units$

4 0

3 years ago

Solve for n please, with work , thank you!

Paul [167]

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\sf1 - 3 n \gt - 1 - 4 ( 2 n - 8 )$

Solve the inequality algebraically.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\sf1 - 3 n \gt - 1 - 4 ( 2 n - 8 )$

Use the distributive property to multiply -4 by 2n-8.

$\sf1-3n>-1-8n+32$

Add -1 and 32 to get 31.

$\sf1-3n>31-8n$

Add 8n to both sides.

$\sf1-3n+8n>31$

Combine -3n and 8n to get 5n.

$\sf1+5n>31$

Subtract 1 from both sides.

$\sf5n>31-1$

Subtract 1 from 31 to get 30.

$\sf5n>30$

Divide both sides by 5. As 5 > 0, the direction of the inequality remains the same.

$\sf \: n>\frac{30}{5} \\$

Divide 30 by 5 to get 6.

$\boxed{ \boxed{ \bf \: n>6 }}$

3 0

3 years ago

Read 2 more answers

A rectangle is 12 feet long and 34 feet wide. What is the area of the rectangle? Enter your answer as a fraction in simplest for

lara [203]

Answer:

A=408 square feet

Step-by-step explanation:

multiply the length by the width and you will have your answer, I don't know about the fraction part though, I hope my info helps though

3 0

3 years ago