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I assume it's 43 <em>thousand</em> and 335, not 43 <em>point</em> 335.
The first 3 from the right is for tens, the second is 10 times stronger because it's for hundreds and the fourth is again 10 times stronger because it's for thousands. Hopefully that's what you meant :)
Sub 2 for x in j(x) and evalueate
then sub that result for x in h(x)
j(2)=-2(2)
j(2)=-4
now sub-4 for x in h(x)
h(-4)=5(-4)-3
h(-4)=-20-3
h(-4)=-23
answer is -23
So the Pythagorean triplet is 8,15and 17
