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aev [14]
3 years ago
12

Consider the relation R on the set S = {1, 2, 3, 4} defined by

Mathematics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

Step-by-step explanation:

a) A relation R is symmetric when it includes the inverse relation, for example if it includes (8,9) then it should also include (9,8), if not, then the relation is not symmetric, you can see that in this case the relation includes (3,4) but not (4,3), therefore it is not symmetric

b) A relation is antisymmetric when it never includes the inverse relation, for example if it includes (8,9) then it can not include (9,8), if it does then it is not antisymmetric. In this case you can see that it first starts with (1,2) but then it also includes (2,1) so then it is not antisymmetric

c) A relation is reflexive if for each number of the domain set it includes the pair that is two times that same number, for example if 8 is in the domain then the relation should include (8,8). if not then it is not reflexive. In this case you can see that the domain S includes 1 but (1,1) is never on the relation or for example (2,2) is also never in the relation.

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His new time compared with the old time was increased by factor of 2

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration (m / s²)v = final velocity (m / s)</em>

<em>u = initial velocity (m / s)</em>

<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Let us now tackle the problem!

This problem is about Kinematics.

In this problem we assume that the unicorn is moving at a constant speed so that the acceleration is zero.

<u>Given:</u>

first distance = d₁ = 50 miles

second distance = d₂ = 300 miles

v₂ = 3 v₁

<u>Unknown:</u>

t₂ : t₁ = ?

<u>Solution:</u>

To find his new time , we will use the following formula.

v_2 = 3 v_1

\frac{d_2}{t_2} = 3 \times \frac{d_1}{t_1}

\frac{300}{t_2} = 3 \times \frac{50}{t_1}

\frac{300}{t_2} = \frac{150}{t_1}

t_2 = \frac{300}{150} \times t_1

\large {\boxed {t_2 = 2 \times t_1} }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Sperm , Whale , Travel

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