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lutik1710 [3]
3 years ago
7

If sec theta = 5/3 and the terminal point determined by theta is in quadrant 4, then:​

Mathematics
2 answers:
timama [110]3 years ago
5 0

Answer:

A. csc 0 = -5/4 or B. cos 0 = 3/5

Juliette [100K]3 years ago
4 0

Answer:

B or A

Step-by-step explanation:

sec(theta) = 1/cos(theta)

cos(theta) = adjacent side / hypotenuse.

The csc(theta), the sin(theta) and the tan(theta) in quad 4 are all minus

Since the cos(theta) is positive in quad 4, B is going to be the answer.

The value for sin(theta) should be sin(theta) = - 4/5 not 2/5

Tan(theta) = - 4/3

Note: 4 is found by using the Pythagorean Theorem because the trigonometric functions are all defined by the sides of a right triangle.

a^2 + b^2 = c^2

a = the adjacent side = 3

b = the opposite side = b

c = the hypotenuse = 5

3^2 + b^2 = 5^2

9 + b^2 = 25

b^2 = 16

b = 4

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10($6.75)+7($1.99)+$15.00=$196.43
34kurt
96/43 = 196/43
the equation is false.
Hope this helps!
5 0
4 years ago
This is my last question on my math test so please help me:
Gnom [1K]

Answer:

Step-by-step explanation:

is number 2

-7,-4...

5 0
3 years ago
A car is traveling at 60 mph and is tailgating another car at distance of only 30 ft. If the reaction time of the tailgater is 0
Sveta_85 [38]

Answer:

44 ft

Step-by-step explanation:

We are given that;

Speed; v = 60 mph

Reaction time;t = 0.5 s

Now, we know that;

Distance = speed x time

Since time is in seconds, let's convert speed to mph to ft/s

From conversion,

1 mph = 1.46667 ft/s

So, 60 mph would give;

60 × 1.46667 ≈ 88 ft/s

Thus, distance his car travels during his reaction time is;

Distance = 88 × 0.5 = 44 ft

6 0
3 years ago
State all possible names for the figure part 3​
qwelly [4]

Answer:

quadrilateral,parallelogram

Step-by-step explanation:

A quadrilateral is a four-sided polygon.

A parallelogram is a quadrilateral with two sets of parallel sides, much like a rectangle, but with no right angles.

7 0
3 years ago
I've been having problems with this for a while...
Rina8888 [55]
Like all problems that involve images within the question, we should definitely try to draw this out. In the picture above, I have done this.

Now, we can see that this is just a simple proportion problem. For every 2.5 cm of height of the flower, we are 2 cm from the opening, or aperture. For every 20 cm of height, how far are we? We can set up the problem like this:

20 ............2.5
-------- = ---------
...x ............. 2

where x is the unknown distance to the aperture from the flower. Now, we just need to get x by itself. A typical way of solving something like this is by doing "butterfly multiplication" which is really just a shortcut haha. Anyway, I can rewrite that equation ^ as:

20×2 = 2.5 × x

Then, to solve for x, we would divide both sides by 2.5. (If you don't know why that is, please let me know and I'll elaborate).

We would then have:

20×2
------- = x
2.5

Which then simplifies to:

x = 16

Try using the same logic for your second question, and if you get stuck, I'd be happy to help! please let me know if any of this doesn't make sense. :)

3 0
4 years ago
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