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3 years ago

Which expression means “ multiply 3 by the sum of m and p “

Mathematics

1 answer:

charle [14.2K]3 years ago

8 0

Answer:

3m+3p

Step-by-step explanation:

Sum of m and p is expressed as;

m + p (sum means addition)

If 3 is multiplied by the sum, this is expressed as;

3(m+p)

Expand

3m + 3p

Hence the required expression is 3m+3p

You might be interested in

Multiply This Expression: -10 ( -a + 5 )

Dovator [93]

You would use distribution. So, in this case, it would be 10a - 50. You use -10 to multiply -a and 5, and you get 10a, and -50.

4 0

3 years ago

Read 2 more answers

I need help on this question plz

Gelneren [198K]

Hello!

The mean is the average. The median is the middle number of the data set, in terms of quantity. The mode is the number that appears the most. The range is the difference between the largest and smallest numbers in the set.

Therefore, our answers are below.

Range: Difference between largest and smallest data piece.

Median: Middle value of a set of data

Mode: most commonly occurring number(s)

Mean: the sum of the data divided by the quantity of the data items.

I hope this helps!

6 0

3 years ago

Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving

lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

$P(x=0) = ^nC_x P^x (1-P)^n^-^x$

$P(x=0) = ^5C_0 (0.4)^0 (1-0.4)^5^-^0$

$P(x=0) = ^5C_0 (0.4)^0 (0.60)^5$

$P(x=0) = 0.778$

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

$= 1 - P(X = 0)$

$= 1 - ^5C_0 (0.4)^0 * (0.6)^5$

$= 1 - 0.0778$

$= 0.9222$

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

$^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 (0.4)^2 (0.6)^3$

$= 0.6826$

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

$= 1 - [^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 * (0.4)^2 (0.6)^3]$

$= 1 - 0.6826$

$= 0.3174$

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0

3 years ago

A bus company has contracted with a local high school to carry 450 students on a field trip. The company has 18 large buses whic

Galina-37 [17]

Answer:

The answer is below

Step-by-step explanation:

Let x represent the big buses and y represent small buses. The large buses can carry 30 students and the small buses can carry 15 students. The total number of students are 450, this can be represented by the inequality:

30x + 15y ≤ 450

They are only 20 drivers, therefore only 20 buses can be used. It is represented by:

x + y ≤ 20

They are only 19 small buses and 18 large buses:

x ≤ 18

y ≤ 19

After plotting the graph, the minimum solution to the graph are at:

A (15,0), B(18,0), C(10, 10), D(18, 2).

The cost function is given as:

The total cost of operating one large bus is $225 a day, and the total cost of operating one small bus is $100 per day.

F(x, y) = 225x + 100y

At point A:

F(x, y) = 225(15) + 100(0) = $3375

At point B:

F(x, y) = 225(18) + 100(0) = $4050

At point C:

F(x, y) = 225(10) + 100(10) = $3250

At point D:

F(x, y) = 225(18) + 100(2) = $4250

The minimum cost is at point C(10, 10) which is $3250

3 0

3 years ago

I have 18 ones 15 hundreds 15 tens 8thousands what number am I

tankabanditka [31]

8 thousands is equal to 8000.
15 hundreds is equal to 1500.
15 tens is equal to 150.
18 ones is equal to 18.

So just add them up.
8000 + 1500 = 9500.
9500 + 150 = 9650.
9650 + 18 = 9668.

The number is 9668

5 0

3 years ago