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Dvinal [7]
3 years ago
6

A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

from the point on the ground halfway between the poles the height of the cable in feet is h(x)=10+(0.1)(x1.5). The cable weighs 10.4 pounds per linear foot. Find the weight of the cable.
Mathematics
1 answer:
gayaneshka [121]3 years ago
8 0

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

h(x)=10+0.1(x^{1.5})

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}

s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx

s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx

s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx

Let 1+0.0225x=t

dx=\frac{1}{0.0225}dt

s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt

s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}

s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}

s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)

s=28.21

Weight of cable=28.21\times 10.4=293.38pound

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Step-by-step explanation:

The missing figure is attached.

The volume of an oblique cylinders and the volume of  a right cylinder can be found with this formula:

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