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Montano1993 [528]
2 years ago
11

Find the area of the composite figure.

Mathematics
1 answer:
Bad White [126]2 years ago
7 0

Answer:

Area = 139.27 m²

Step-by-step explanation:

Area of the composite figure = area of rectangle + area of semicircle

= (L*W) + ½(πr²)

L = 10 m

W = 10 m

r = ½ of 10 = 5 m

Plug in the values

Area = (10*10) + ½(π*5²)

Area = 100 + 39.27

Area = 139.27 m²

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Find the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)
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The coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4) is (\frac{-17}{5} ,\frac{2}{5} )

Explanation :

the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)

Apply section formula to find coordinates of point Q

(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n} )

Ratio m:n is 2:3 and point R is (x1,y1) , point S is (x2,y2)

Substitute all the values inside the formula

(\frac{2(2)+3(-7)}{2+3} , \frac{2(4)+3(-2)}{2+3} )\\\\(\frac{-17}{5} ,\frac{2}{5} )

The coordinates of point Q is (\frac{-17}{5} ,\frac{2}{5} )

Learn more :  brainly.com/question/13878373

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3 years ago
there are 3 teams of 18 employees working today company policy says that we need to have one supervisor for every 8 employees on
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The <span> answer  is 6.75. Since if you divide the number by 8 you get 6.75.</span>
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Two brothers, Kevin and Greg, each inherit S43000. Kevin invests his inheritance in a savings account with an annual return of 1
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S1548.

Step-by-step explanation:

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Kevin : After 1 year he has 43,000 * 0.017 = S731.

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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
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Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

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Generally 90% confidence interval is mathematically represented as  

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Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
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