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3 years ago

Solve for C: C + 8 = -11 C = _____

Mathematics

2 answers:

KIM [24]3 years ago

8 0

Subtract 8 from both sides
C=-11-8
Simplify-11-8 to -19
C = -19

stiv31 [10]3 years ago

7 0

Well what +8 will be -11.
Let’s take this as positives.
8+11=19
Sooo
-19+8=-11
C=-19

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3.a. Solve the following equations.

ozzi

Answer:

1. Solving $\frac{1}{3}(2x-1)-\frac{1}{4}(2x+1)=\frac{1}{12}(2-x)$ we get x=3

2. Solving $\frac{x-2}{4}+\frac{2x-1}{4}=x-\frac{1}{2}$ we get x=-1

Step-by-step explanation:

We need to solve the equations:

1. $\frac{1}{3}(2x-1)-\frac{1}{4}(2x+1)=\frac{1}{12}(2-x)$

Expanding the brackets

$\frac{2x}{3}-\frac{1}{3} -\frac{2x}{4}-\frac{1}{4} =\frac{2}{12}-\frac{x}{12} \\\frac{2x}{3}-\frac{1}{3} -\frac{x}{2}-\frac{1}{4} =\frac{1}{6}-\frac{x}{12}$

Taking LCM on left side we get 12

$\frac{2x*4-1*4-x*6-1*3}{12}= \frac{1}{6}-\frac{x}{12}\\\frac{8x-4-6x-3}{12}= \frac{1}{6}-\frac{x}{12}\\\frac{8x-6x-3-4}{12}= \frac{1}{6}-\frac{x}{12}\\\frac{2x-7}{12}= \frac{1}{6}-\frac{x}{12}\\\frac{2x}{12}-\frac{7}{12}= \frac{1}{6}-\frac{x}{12}$

Add 7/12 on both sides

$\frac{2x}{12}-\frac{7}{12}+\frac{7}{12} = \frac{1}{6}-\frac{x}{12}+\frac{7}{12}\\\frac{x}{6}=\frac{1*2-x+7}{12}\\ \frac{x}{6}=\frac{-x+9}{12} \\\frac{x}{6}=-\frac{x}{12} +\frac{9}{12}\\ \frac{x}{6}=-\frac{x}{12} +\frac{3}{4}$

Adding x/12 on both sides and simplifying

$\frac{x}{6}+\frac{x}{12} =-\frac{x}{12} +\frac{3}{4}+\frac{x}{12}\\\frac{x*2+x}{12}=\frac{3}{4}\\\frac{3x}{12}= \frac{3}{4}\\$

Multiply both sides by 12/3

$\frac{3x}{12}*\frac{12}{3}=\frac{3}{4}*\frac{12}{3} \\Simplifying:\\x=3$

So, solving $\frac{1}{3}(2x-1)-\frac{1}{4}(2x+1)=\frac{1}{12}(2-x)$ we get x=3

2. $\frac{x-2}{4}+\frac{2x-1}{4}=x-\frac{1}{2}$

Taking LCM and solving:

$\frac{x-2+2x-1}{4}=\frac{2x-1}{2}\\\frac{x+2x-1-2}{4}=\frac{2x-1}{2}\\\frac{3x-3}{4}=\frac{2x-1}{2}\\$

Cross multiplying

$2(3x-3)=4(2x-1)\\6x-6=8x-4\\Combining\ like\ terms \ :\\6x-8x=-4+6\\-2x=2\\x=-1$

So, solving $\frac{x-2}{4}+\frac{2x-1}{4}=x-\frac{1}{2}$ we get x=-1

4 0

3 years ago

Simplify. (5b2−3b+2)+(2b−4) A.5b2+5b+6 B.5b2−5b−6 C.5b2−b−2 D.6b4−2

xxTIMURxx [149]

Answer:

5b2 - b -2

Step-by-step explanation:

The answer is (c)

3 0

2 years ago

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If you apply the changes below to the absolute value parent function,

QveST [7]

Answer:

$F(x) = |x|$

And we need to apply some transformations. The first part is hift 8 units left. And we need to do this:

$F(x) = |x+8|$

Then we need to apply the second transformation Shift 3 units down. and we can do this:

$F(x) = |x+8|-3$

Step-by-step explanation:

For this case we have the following function given:

$F(x) = |x|$

And we need to apply some transformations. The first part is hift 8 units left. And we need to do this:

$F(x) = |x+8|$

Then we need to apply the second transformation Shift 3 units down. and we can do this:

$F(x) = |x+8|-3$

6 0

3 years ago

For the following system, determine if a steady state exists and give the steady state value. The population of a colony of squi

Anettt [7]

Answer:

Option A)

$\displaystyle\lim_{t\to\infty}~p(t) = k$

Step-by-step explanation:

We are given the following on the question:

$p(t) =\displaystyle\frac{4000}{4+e^{-0.02t}}$

where p(t) is the population of a colony.

For steady state solution we evaluate:

$\displaystyle\lim_{t\to\infty}~p(t)\\\\= \lim_{x\to\infty} \frac{4000}{4+e^{-0.02t}}\\\\=\frac{4000}{4+e^{-\infty}}\\\\=\frac{4000}{4}\\\\= 1000$

Thus, the steady state solution is a constant, k = 1000.

Thus, the correct answer is

Option A)

$\displaystyle\lim_{t\to\infty}~p(t) = k$

8 0

3 years ago

50 POINTS PLEASE HELP!!

Vinvika [58]

Answer: A. 35

Step-by-step explanation: The largest prime number less than 50. The largest number less than 50 is 49, but it is not prime, because 49=7·7. The previous number is 48, but it is also composite, because 48=2·2·2·2·3. The previous number is 47, it is prime.

The smallest composite number greater than 10. The smallest number greater than 10 is 11, but it is prime. The next number is 12, it is composite, because 12=2·2·3.

The difference between the largest prime number less than 50 and the smallest composite number greater than 10 is 47-12=35.

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4 years ago

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