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mr Goodwill [35]
3 years ago
13

Using a coordinate plane, draw a right triangle so the two shorter sides are 3 and 4 units long

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

10 units

Step-by-step explanation: Using a coordinate plane, draw a right triangle so the legs are 6 and 8 units long, then use your formula A to the second power + B to the second power equals C to the second power.


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The heights​ (in inches) and pulse rates​ (in beats per​ minute) for a sample of 1111 women were measured. Using technology with
Snowcat [4.5K]

Answer:

There is evidence to support the claim that there is a linear correlation between the heights and pulse rates of​ women

Step-by-step explanation:

given that the heights​ (in inches) and pulse rates​ (in beats per​ minute) for a sample of 11 women were measured.

correlation coefficient r = 0.7200

H_0 : r=0\\H_a: r \neq 0

(two tailed test at 5% significance level)

r difference = 0.7200

Std error of r = \sqrt{\frac{1-r^2}{n-2} } \\=\sqrt{\frac{0.4816}{9} } \\=0.2313

Test statistic t = r difference/std error = 3.1128

df =9

p value=0.012458

since p <alpha, we reject H0

There is evidence to support the claim that there is a linear correlation between the heights and pulse rates of​ women

3 0
4 years ago
Since at t=0, n(t)=n0, and at t=[infinity], n(t)=0, there must be some time between zero and infinity at which exactly half of t
Ostrovityanka [42]

An expression for this timet-half will be given as ln(2) / λ ≈ 0.693 / λ

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

1) Equation given:

← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N9t) = Ne^{-\lambda t}

3) Solving for α (remember α is λ)

N_{t-half}=\dfrac{N_o}{2}=N_oe^{-\alpha t}

\dfrac{1}{2} = e^{-\alpha t}2=e^{-alpha t}\alpha t=In(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ

Therefore expression for this timet-half will be given as ln(2) / λ ≈ 0.693 / λ

To know more about an expression follow

brainly.com/question/723406

#SPJ4

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kotykmax [81]
5/12 instead of the full amount
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