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podryga [215]
2 years ago
15

For every 100,000 baby boys born in the US in 2018, the Office of National Statistics (ONS) used current mortality rates to pred

ict the number that would die at each age. According to the ONS, the data is skewed to the left - with most males born in 2018 predicted to die in their eighties and comparatively few predicted to die as babies. The two measures of center for the life expectancy of US males born in the 2018 are 79 years and 82 years.
Which number best represents the median life expectancy for US males born in 2018 and which number best represents the mean?


1- 79 years is the median and 82 years is the mean

2- 79 years is the mean and 82 years is the median.
Mathematics
1 answer:
Inessa [10]2 years ago
5 0

Answer:

2 - 79 years is the mean and 82 years is the median.

Step-by-step explanation:

In a given skewed to the left graph, to be able to distinguish between the two measures of center for this expectancy study, the mean is relatively smaller than the median in a skewed left distribution curve.

In this study, The two measures of center for the life expectancy of US males born in the 2018 are 79 years and 82 years. Thus, 79 years is the mean and 82 years is the median.

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Evgesh-ka [11]
Well 88 is 88% and 98% but if you round 88 would turn into 90% and 98 would become 100%. and 100% minus 90% is 10% so the broadcaster had about a 10% error.
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3 years ago
You want to obtain a sample to estimate how much parents spend on their kids birthday parties. Based on previous study, you beli
zhuklara [117]

Answer:

We need to sample at least 1069 parents.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many parents do you have to sample?

We need to sample at least n parents.

n is found when M = 4, \sigma = 79.5. So

M = z*\frac{\sigma}{\sqrt{n}}

4 = 1.645*\frac{79.5}{\sqrt{n}}

4\sqrt{n} = 1.645*79.5

\sqrt{n} = \frac{1.645*79.5}{4}

(\sqrt{n})^{2} = (\frac{1.645*79.5}{4})^{2}

n = 1068.92

Rounding up

We need to sample at least 1069 parents.

6 0
3 years ago
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Step-by-step explanation:

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A researcher wanted to see if giving a selective serotonin reuptake inhibitor (anti-depressant) would decrease the number of sel
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Answer:

a. The mean of the sample is M=35.

The variance of the sample is s^2=39.125.

The standard deviation of the sample is s=6.255.

b. z=-1.6

c. SEM = 2.212

Step-by-step explanation:

The mean of the sample is M=35.

The variance of the sample is s^2=39.125.

The standard deviation of the sample is s=6.255.

<u>Sample mean</u>

<u />M=\dfrac{1}{8}\sum_{i=1}^{8}(27+25+32+40+43+37+35+38)\\\\\\ M=\dfrac{277}{8}=35

<u>Sample variance and standard deviation</u>

<u />s^2=\dfrac{1}{(n-1)}\sum_{i=1}^{8}(x_i-M)^2\\\\\\s^2=\dfrac{1}{7}\cdot [(27-(35))^2+(25-(35))^2+(32-(35))^2+(40-(35))^2+(43-(35))^2+(37-(35))^2+(35-(35))^2+(38-(35))^2]\\\\\\

s^2=\dfrac{1}{7}\cdot [(58.141)+(92.641)+(6.891)+(28.891)+(70.141)+(5.64)+(0.14)+(11.39)]\\\\\            s^2=\dfrac{273.875}{7}=39.125\\\\\\s=\sqrt{39.125}=6.255

b. If the population mean is 45, the z-score for M=35 would be:

z=\dfrac{M-\mu}{\sigma}=\dfrac{35-45}{6.255}=\dfrac{-10}{6.255}=-1.6

c. The standard error of the mean (SEM) of this group is calculated as:

SEM=\dfrac{s}{\sqrt{n}}=\dfrac{6.255}{\sqrt{8}}=\dfrac{6.255}{2.828}=2.212

4 0
3 years ago
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