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podryga [215]
3 years ago
15

For every 100,000 baby boys born in the US in 2018, the Office of National Statistics (ONS) used current mortality rates to pred

ict the number that would die at each age. According to the ONS, the data is skewed to the left - with most males born in 2018 predicted to die in their eighties and comparatively few predicted to die as babies. The two measures of center for the life expectancy of US males born in the 2018 are 79 years and 82 years.
Which number best represents the median life expectancy for US males born in 2018 and which number best represents the mean?


1- 79 years is the median and 82 years is the mean

2- 79 years is the mean and 82 years is the median.
Mathematics
1 answer:
Inessa [10]3 years ago
5 0

Answer:

2 - 79 years is the mean and 82 years is the median.

Step-by-step explanation:

In a given skewed to the left graph, to be able to distinguish between the two measures of center for this expectancy study, the mean is relatively smaller than the median in a skewed left distribution curve.

In this study, The two measures of center for the life expectancy of US males born in the 2018 are 79 years and 82 years. Thus, 79 years is the mean and 82 years is the median.

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Serga [27]

Answer:

no solutions

Step-by-step explanation:

distribute the 4 to get:

-12b - 56 = -12b

add 12b to each side to get:

-56 = 0

since -56 does not equal 0 there are no solutions

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2 years ago
Given the expression below, write an equivalent expression that does not contain parentheses.​
sertanlavr [38]

Answer:

-2x - 12 - 2

Step-by-step explanation:

  1. Apply the distributed property: -2x - 12 - 2

I hope this helps!

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This is the answer for both number 9 and number 11.
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6 0
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A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and
goldenfox [79]

Answer:

Option D

Step-by-step explanation:

A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and constructs a 99% confidence interval for the true mean finish time to be (86.05, 99.38) minutes.

Assuming the reporter performed the calculations correctly, which of the following statements are appropriate interpretations of this confidence interval?

We can expect that 99% of confidence intervals created using the same method the reporter used will contain the true mean run time for runners of this race.

4 0
3 years ago
A realtor collects the data set given in DS 12.2.4 concerning the sizes of a random selection of newly constructed houses in a c
Yuliya22 [10]

The table is missing in the question. The table is attached below.

Solution :

Let X = appraised value

    Y = area (square feet)

The regression line is given by :

$\hat y = b_0+b_1X$

$b_1=\frac{n\sum XY-\sum X \sum Y}{n \sum X^2-(\sum X)^2}$

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  $=12.3267$

$b_0=\frac{\sum Y}{n}-b_1\frac{\sum X}{n}$

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  $b_0=452.0841$

The regression line is :

$\hat Y = 452.0841+12.3267 X$

To estimate the error variance, we have:

Error variance, $\sigma =\sqrt{\frac{\sum (Y-\hat Y)^2}n-2{}}$

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