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vivado [14]
3 years ago
7

Mr. Wilson wants to park his car in his parking garage. To find the cost, he uses the equation D= 3H+6, where D represents the t

otal amount, in dollars, charged for parking a car for H hours. If Mr. Wilson spent $30, how many hours did he park in the parking garage?
Mathematics
1 answer:
charle [14.2K]3 years ago
7 0

Answer: 8\ hours

Step-by-step explanation:

You know that Mr. Wilson uses the following equation to find the cost:

D= 3H+6

Then, if Mr. Wilson spent $30, you can follow these steps in order to calculate how many hours he parked in the parking garage:

1. You need to substitute D=30 into the given equation:

30= 3H+6

2. Now, you must solve for "H":

30= 3H+6\\\\30-6=3H\\\\24=3H\\\\\frac{24}{3}=H\\\\H=8

Therefore, based on the result, you can conclude that Mr. Wilson parked his car in the parking garage for 8 hours.

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If angle EFH(5x+1)’ angle HFG(62 degrees) and angle EFG (18x+11) find each measurement
zloy xaker [14]

Answer:

∠EFH = 21°

∠HFG = 62°

∠EFG = 83°

Step-by-step explanation:

The diagram showing the angles has been attached to this response.

From the diagram, it can be deduced that;

Angle EFG = angle EFH + angle HFG

=> ∠EFG = ∠EFH + ∠HFG                -------------------(i)

From the question:

∠EFH = (5x + 1)°                    -------------(ii)

∠HFG = 62°                          -------------(iii)

∠EFG = (18x + 11)°                 -------------(iv)

<em>Substitute these values into equation (i) as follows;</em>

(18x + 11) = (5x + 1) + 62

=> 18x + 11 = 5x + 1 + 62

<em>Collect like terms and solve for x</em>

18x - 5x = 1 + 62 - 11

13x = 52

x = 4

Now, to get each measurement, substitute x = 4 into each of equations (ii) - (iv)

∠EFH = (5x + 1)°

∠EFH = (5(4) + 1)°

∠EFH = (20 + 1)°

∠EFH = 21°

∠HFG = 62°              [<em>Does not depend on x</em>]

∠EFG = (18x + 11)°

∠EFG = (18(4) + 11)°

∠EFG = (72 + 11)°

∠EFG = 83°

<u>Conclusion:</u>

∠EFH = 21°

∠HFG = 62°

∠EFG = 83°

8 0
3 years ago
Solve system of equation algebraically <br> y = 2x - 3<br> x + y = 18
natima [27]

Answer:

x = 7

y = 11

Step-by-step explanation:

Given the system;

y = 2x - 3

x + y = 18

1. Approach

The easiest way to solve this system of equations is to solve the second equation for the variable (y). Then add the systems, use algebra to solve for the value of (x), then substitute that value back into one of the original equations to solve for the value of (y). Another name for the method in use is the method of elimination, this is when a [erspm manipulates one of the equations in a system of the equation such that when they add the equations, one of the variables eliminatates. Thus, they can solve for the other variable and the backsolve for the value of the unknown variable.

2. Solve one of the equations for a variable

Manipulate the system such that each equation is solved for the same variable,

x + y = 18

Inverse operations,

x + y = 18

-18        -18

x + y - 18 = 0

   -y         -y

x - 18 = -y

3. Use elimination

Now substitute this back into the original system,

y = 2x - 3

-y = x - 18

Add the systems,

y = 2x - 3

-y = x - 18

_________

0 = 3x - 21

Inverse operations,

0 = 3x - 21

+21       +21

21 = 3x

/3    /3

7 = x

4. Find the value of the unknown variable

Backsovle to find the value of (y),

x + y = 18

Substitute,

7 + y = 18

Inverse operations,

7 + y = 18

-7        -7

y = 11

3 0
2 years ago
Read 2 more answers
The sum of twice a number and 5 is at most 15. What are 3 possible<br> values for the number?
sdas [7]

Answer: the answer is 36

Step-by-step explanation:

4 0
2 years ago
The sum of two numbers is 82. One number is three less than four times the other. Find the two numbers.
kondor19780726 [428]

Answer:

17 , 65

Step-by-step explanation:

x+ y = 82

y = 4x - 3

=====================

Put the second equation into the first.

x + 4x - 3 = 82

5x = 85

x = 85/5

x = 17

17 + y = 82

x = 82 - 17

x = 65

8 0
3 years ago
80% of a number is 96.
pantera1 [17]
80/100 = 96/x
80x=9600
8x=960
x=120
120/4
30
so the answer is b
6 0
3 years ago
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