Question

At a pressure of one atmosphere methane boils at −161°C and freezes at −182.5°C. Consider a temperature scale where the boiling point of methane is 100.0°M and the freezing point is 0°M. Determine the temperature on the Methane scale that corresponds to the absolute zero point on the Kelvin scale. °M

Answer 1

Answer:

$-421.627906977\^{\circ}M$

Explanation:

Absolute zero in the Kelvin scale = -273.15 °C

Temperature difference in the boiling and freezing point

$-161-(-182.5)=21.5\ ^{\circ}C$

Change in 21.5°C = Change of 100°C in M

$1^{\circ}C=\dfrac{100}{21.5}=4.6511627907\ ^{\circ}M$

Difference in the Celsius scale

$-182.5-(-273.15)=90.65\ ^{\circ}C$

Change in $90.65\ ^{\circ}C$ corresponds to

$4.6511627907\times 90.65=421.627906977\ ^{\circ}M$

Therefore the absolute zero in the Methane scale is

$-421.627906977\ ^{\circ}M$