<u>Voltage:</u>
It is basically the difference between the charges of the materials on the ends of the Wire
<em>also known as potential difference</em>
It is very similar to the movement of air, it moves from higher density to lower density. in this case, the change in density is the potential difference
So, since voltage is the difference between the charge available on the ends of a wire. Even if the wire splits in parallel circuit, the difference of the charges remains the same
<em>the more the potential difference, the faster electrons will move to the material with lower charge</em>
<u>Current:</u>
Current is the amount of electrons moving through a cross-section of a wire in a period of time
So basically, it is the amount of electrons that move across a given point on a wire in a period of time
If the wire splits, we will have the same amount of electrons moving through as they would if the wire was not split but now, the electrons passing are divided and hence, if we measure the current after the split, we will find that we have a lower current
that's because we have less charge moving through the cross-section of the wire since some of those electrons are moving through a different wire
That's why the current splits in a parallel circuit
The main activity that is involved in studying of physics is the study of natural laws. The study of physics has to do with many aspects of the universe. Physics majorly looks into the natural laws that operate in the universe and describe how they affect matter in relation to time.
Answer: maximum height= 40.8m
Explanation: shown in the attachment.
Goodluck
Answer:a) 34.5 N; b) 24.5 N; c) 10 N; d) 1J
Explanation: In order to solve this problem we have to used the second Newton law given by:
∑F= m*a
F-f=m*a where f is the friction force (uk*Normal), from this we have
F= m*a+f=5 Kg*2 m/s^2+0.5*5Kg*9.8 m/s^2= 34.5 N
then f=uk*N=0.5*5Kg*9.8 m/s^2= 24.5N
the net Force = (34.5-24.5)N= 10 N
Finally the work done by the net force is equal to kinetic energy change so
W=∫Force net*dr= 10 N* 0.1 m= 1J