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Vinvika [58]
3 years ago
11

When a population changes dramatically over time, what would this most likely lead to?

Physics
2 answers:
Shtirlitz [24]3 years ago
8 0
It’s B or C B if it’s in breeding but C if the population is dropping dramatically
Alinara [238K]3 years ago
6 0

Answer:

B

Explanation:

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Explain why the bright spectral lines of light emitted from the atoms of an element are unique to that element
eduard
 <span>If you want the Lewis diagram of arsenic, it is a single element, and not much of a "structure". Simply place five dots on the four sides of an imaginary square around the symbol As. Two of the dots are paired, three are unpaired.

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4 0
3 years ago
Force is a vector because it has both ___
scoray [572]

Answer:

C. Size and Direction

6 0
3 years ago
A 1502.7 kg car is traveling at 33.1 m/s when
Bond [772]

By definition of average acceleration,

<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²

Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:

∑ <em>F</em> = (1502.7 kg) (-2.78 m/s²) ≈ -4188.38 N ≈ -4200 N

If you just want the magnitude, drop the negative sign.

5 0
3 years ago
A car is driving at 85 km/h and the driver spots a stop sign ahead. What coefficient of friction is needed to stop the car at th
almond37 [142]

Answer:

μ = 0.0315

Explanation:

Since the car moves on a horizontal surface, if we sum forces equal to zero on the Y-axis, we can determine the value of the normal force exerted by the ground on the vehicle. This force is equal to the weight of the cart (product of its mass by gravity)

N = m*g (1)

The friction force is equal to the product of the normal force by the coefficient of friction.

F = μ*N (2)

This way replacing 1 in 2, we have:

F = μ*m*g (2)

Using the theorem of work and energy, which tells us that the sum of the potential and kinetic energies and the work done on a body is equal to the final kinetic energy of the body. We can determine an equation that relates the frictional force to the initial speed of the carriage, so we will determine the coefficient of friction.

\frac{1}{2} *m*v_{i}^{2}-(F*d)=  \frac{1}{2} *m*v_{f}^{2}

where:

vf = final velocity = 0

vi = initial velocity = 85 [km/h] = 23.61 [m/s]

d = displacement = 900 [m]

F = friction force [N]

The final velocity is zero since when the vehicle has traveled 900 meters its velocity is zero.

Now replacing:

(1/2)*m*(23.61)^2 = μ*m*g*d

0.5*(23.61)^2 = μ*9,81*900

μ = 0.0315

5 0
3 years ago
​A ​very ​long ​insulating ​cylinder ​of ​charge ​of ​radius ​2.50 ​cm ​carries ​a ​uniform ​linear ​density ​of ​15.0 ​nC/m. ​(
Pavlova-9 [17]

Answer:

r2 = 2.401557  cm

distance = 0.10 cm

Explanation:

given data

​radius ​= 2.50 ​cm

​density ​= ​15.0 ​nC/m

voltmeter ​read =  ​175

solution

we know here potential difference that is express as

ΔV = \frac{\lambda }{2\pi \epsilon _o} ln\frac{r2}{r1}     ...........1

so here

ln\frac{r2}{r1} = 2\pi \epsilon _o \times \frac{\triangle V}{\lambda }  

as here \lambda is linear charge density  

\frac{r2}{r1} = e^{2\pi \epsilon _o \times \frac{\triangle V}{\lambda }}  

r2 = r1 × e^{2\pi \epsilon _o \times \frac{\triangle V}{\lambda }}  

r2 = 2.40 × e^{2\pi 8.85\times 10^{-12} \times \frac{175}{15\times 10^{-6} }}  

r2 = 2.401557  cm

and

here distance above surface will be

distance = r1 - r2

distance =  2.50 - 2.40

distance = 0.10 cm

4 0
3 years ago
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