Answer: 2nd most popular country = 15895 students
most popular country = 24390 students
Step-by-step explanation:
Total students: 40,285
2nd most popular country = x students
most popular country = x + 8,495 students
x + x + 8495 = 40285
2x + 8495 = 40285
2x = 40285 - 8495
2x = 31790
x = 15895
2nd most popular country = x = 15895 students
most popular country = x + 8,495 = 15895 + 8,495 = 24390 students
-2(-2)^4 + 5(-2)^2 - 4
-2(-2)= 4. 4^4= 16
5(-2)= -10. -10^2= 100 - 4= 96
96 + 16= 112
Answer: 112
X is 66 degrees, you just subtract 24 to 90 and it gives you 66.
Answer:
|-2| + 2
Step-by-step explanation:
-4 / 2-5<em>i</em>
cos (<em>x</em>) / 1 - sin squared (<em>x</em>)
<u>|-2| + 2</u>
Answer:
Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Step-by-step explanation:
Given the figure with dimensions. we have to find the area of given figure.
Area of figure=ar(1)+ar(2)+ar(3)
Area of region 1 = ar(ANGI)+ar(AIB)
![=L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha](https://tex.z-dn.net/?f=%3DL%5Ctimes%20B%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height%5C%5C%5C%5C%3D%5B1500%5Ctimes%20%285000-2000-1500%29%5D%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%283000-1500%29%5Ctimes%20%285000-2000-1500%29%5C%5C%5C%5C%3D3375000m%5E2%3D337.5ha)
Area of region 2 = ar(DHBC)

Area of region 3 = ar(GFEH)

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha
=987.5 ha
Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.
Let the fencing be done through x m downward from B which divides the two into equal area.
⇒ Area of upper part above fencing=Area of lower part below fencing
⇒
Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.