Which statements are true about finding the difference of the expressions? Select three options? 3p + 1/6p - 2p

Aiden and Haisem are going to eat the same amount of hamburgers and fries, but from different restaurants. Aiden goes to Burger

Paha777 [63]

Answer:

the burgers be 3 and fries be 2

Step-by-step explanation:

The computation is shown below:

Let us assume burgers be x

And, the fries be y

Now according to the questiojn

1.25x + 0.50y = $4.75

1.50x + 0.99y = $6.48

Now multiply by 1.2 in the first equation

1.50x + 0.6y = $5.70

1.50x + 0.99y = $6.48

-0.39y = -0.78

y = 2

Now put the value of y in any of the above equation

1.25x + 0.50(2) = $4.75

x = 3

Hence, the burgers be 3 and fries be 2

6 0

3 years ago

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

3 years ago

I am being timed. Please help

baherus [9]

Answer:

It would be 8 PM.

Step-by-step explanation:

If you keep decreasing 23 by 7 till you get to -5, it would have to be decreased 4 times to get to -5. This means that the time would have to go up 4 times the 45 minute rate, which would be 3 hours. 5 pm + 3 hours is 8 PM.

5 0

4 years ago

You bought 50 shares of stock at $55 per share and sold them for $61 per share. The sale involves a broker’s commission of $0.30

malfutka [58]

Answer:

The profit made is;

b) $285)

Step-by-step explanation:

The given parameters are;

The number of shares bought, n = 50

The price each share is bought, CP = $55

The amount at which each share is sold, SP = $61

The amount the broker received per share, E = $0.30

Therefore, the amount of profit, 'P', is given as follows;

P = n × (SP - CP - E)

By substituting the values for the variables, we have;

P = 50 × (61 - 55 - 0.3) = 285

The amount made as profit, P = $285.00.

6 0

3 years ago

To rent office space for your business, you must pay a one time fee of $1000 and pay rent of $800 per month.

Lelu [443]

Answer:

Step-by-step explanation:

a) y=800x+1000=800(12)+1000

b)y=1000x (15 months)

5 0

4 years ago

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Which statements are true about finding the difference of the expressions? Select three options? 3p + 1/6p - 2p - 3/2p​

Which statements are true about finding the difference of the expressions? Select three options? 3p + 1/6p - 2p - 3/2p