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2 years ago

What is the justification for each step in the solution of the equation?

Mathematics

2 answers:

jeka57 [31]2 years ago

6 0

13x−4=−36−27x+12: Distributive property

13x−4=−24−27x: Combine like terms

40x=−20: Addition Property of equality

Crazy boy [7]2 years ago

6 0

<h2>Answer with Step-by-step explanation:</h2>

13x−4= −9(4+3x)+12 (Given)

13x−4= −36−27x+12 (Distributive property: -9(4+3x)= -36-27x)

13x−4= −24−27x (combining like terms on each side: -36+12= -24)

40x−4=−24 (Addition Property of Equality: adding 27x on both sides )

40x= −20 (Addition Property of Equality: adding 4 on both sides )

x= −1/2 (Division Property of Equality: dividing both sides by 40)

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Determine the distance between the following two points. (round to the nearest hundredths)

padilas [110]

Answer:

$d=7.07$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>:

$d=\sqrt{(3-(-2))^2+(-4-1)^2}$

$d=\sqrt{(3+2)^2+(-5)^2}$

$d=\sqrt{(5)^2+25}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

$d=7.07$

5 0

2 years ago

How would you describe the shape of the normal distribution?

RUDIKE [14]

The shape of the normal distribution is bell shape and it is also symmetrical from the left and right sides about the origins (mean).

What is a normal distribution?

A normal distribution is a function on some random variables, which represent the set of all those random variables in a symmetrical bell shape about the mean value.

It shows that the probability of occurrence of some data which is distributed over a function is more at or around the mean.

It is also known as probability distribution curve.

The normal distribution has two parameters:

Mean

Standard deviation

What is the shape of the normal distribution?

The normal distribution curve is at it's peak at the mean value. This shows that the probability of occurrence of the data or value is more concentrated or distributed about the mean. It is also symmetric about the mean. As we more further from the mean, we see that the normal distribution curve gradually decreases showing that the probability of occurrence of the data or the values decreases. The shape that this curve forms is like a bell-shaped. So the shape of normal distribution is bell shape.

Hence, the shape of the normal distribution is bell shape and it is also symmetrical from the left and right sides about the origins (mean).

Know more about "normal distribution" here: brainly.com/question/15103234

#SPJ4

5 0

10 months ago

For circle O, mCD=125° and m

Burka [1]

CA is a diameter of the circle, so $m\widehat{AC}=180^\circ$ , which means $m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ$ . Then $m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ$ .

This means $m\angle CBO=55^\circ-35^\circ=20^\circ$ . Also, if $m\angle AOB=55^\circ$ , then $m\angle BOC=180^\circ-55^\circ=125^\circ$ , which in turns tells us that $m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ$ .