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3 years ago

Simple geometry problem

Mathematics

2 answers:

baherus [9]3 years ago

8 0

you should probably try reading the question first.

the arc measure and radius are given to you. now, it is up to you to use your brain and put two and two together. good luck.

vova2212 [387]3 years ago

7 0

Answer:

Step-by-step explanation:

I gather that you need to find the area of the sector and then subtract from it the area of the segment to get the area of the triangle (although there are other ways in which to find the area of the triangle).

The area of a sector is:

$A=\frac{\theta}{360}\pi r^2$ where our angle is given as 34, pi is 3.1415, and the radius is 5:

$A=\frac{34}{360}(3.1415)(25)$ and if you multiply and divide that all out you get that the area of the sector is:

A = 7.417

Now subtract from it the area of the segment, 2.209. to get the area of the triangle:

7.417 - 2.209 = 5.208

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3 cups 6oz + 2 cups 9oz

Liono4ka [1.6K]

1 cup is equal to 8 oz, so
3 cups x 8 = 24 oz.
you'll do the same for the two cups
2 x 8 = 16 oz
so adding them all together will be
24 + 6 + 16 + 9 = 55 total oz.

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3 years ago

Write an equivalent exponential expression for “five to the third power. " Evaluate the expression.

Likurg_2 [28]

$5^{3}$ is the equivalent to "five to the third power"

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3 years ago

Read 2 more answers

Which choice is a graph of the solution set for 12 - X < 8?<br> Pleaseeeee helpppppp NUMBER 14

yarga [219]

Answer:

Hope this helps!

explanation:

we solve the inequality and to do that we must first subtract 12 from both sides, which gets us -x<-4, then we divide both sides by -1, which gives us x>4, since we have to flip the sign when we divide by a negative. when we graph this, there will be a circle around 4 and the arrow pointing to the right, since it's greater than.

7 0

3 years ago

According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i

Ierofanga [76]

Answer:

a) $P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

b) $P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

c) For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

And replacing we got:

$P(X\geq 8)=0.0000779$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n=10 ,p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:

$X \sim Binom(n=10, p=0.2)$

Part a

We want to find this probability:

$P(X=2)$

And using the probability mass function we got:

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

Part b

For this case we want this probability:

$P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

We can find the individual probabilities and we got:

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

Part c

For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

3 0

3 years ago

an experiment consists of flipping a fair coin 4 times. What is the probability of obtaining at least one head?

Dvinal [7]

$\mathbb P(X\ge1)=1-\mathbb P(X=0)$

The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is $\dfrac1{2^4}=\dfrac1{16}$ .

So the desired probability is

$1-\dfrac1{16}=\dfrac{15}{16}$

7 0

3 years ago